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Vinil7 [7]
3 years ago
11

3. What mass of copper could be deposited from a copper(II) Sulphate solution using a current of 5.0 A over 100 seconds? ( F =96

,500C,Charge of Cu in CuSO4 = +2)​
Chemistry
1 answer:
arsen [322]3 years ago
8 0

Mass of copper : 0.165 g

<h3>Further explanation</h3>

Given

5.0 A over 100 seconds

Required

Mass of copper

Solution

Faraday's law:

<em>The mass of the substance formed at each electrode is proportional to the electric current flowing in the electrolysis</em>

<em />\tt W=\dfrac{e.i.t}{96500}<em />

e = Ar / valence = eqivalent weight

i = current

t = time

W = weight

CuSO₄ ----> Cu²⁺ + SO₄²⁻

Cu ----> Cu²⁺ + 2e

e = Ar/2

= 63,5/2 = 31,75

\tt W=\dfrac{31.75\times 5\times 100}{96500}=0.165~g

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What is the density of a gas with a molar mass of 28.26 grams per mole at 3.510 ATM in 237 Kelvin​
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<h3><u>Answer;</u></h3>

= 5.1 g/L

<h3><u>Explanation;</u></h3>

Using the equation;

PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.

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Therefore; We can find the volume and thus get the density.

<em>V = nRT/P</em>

<em>    = (1 × 0.08206 × 237)/3.510</em>

<em>     = 5.5408 L</em>

<em>Hence; Density = mass/volume </em>

<em>                           = 28.26 g/5.5408 L</em>

<em>                           = 5.1 g/L</em>

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What would be the final volume (in mL) of the aqueous potassium fluoride which was prepared by dissolving 8.0 g of potassium flu
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