3. What mass of copper could be deposited from a copper(II) Sulphate solution using a current of 5.0 A over 100 seconds? ( F =96
1 answer:
Mass of copper : 0.165 g
<h3>Further explanation</h3>Given
5.0 A over 100 seconds
Required
Mass of copper
Solution
Faraday's law:
<em>The mass of the substance formed at each electrode is proportional to the electric current flowing in the electrolysis</em>
<em /><em />
e = Ar / valence = eqivalent weight
i = current
t = time
W = weight
CuSO₄ ----> Cu²⁺ + SO₄²⁻
Cu ----> Cu²⁺ + 2e
e = Ar/2
= 63,5/2 = 31,75
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Answer:
3.3557047 mL
Explanation:
The density can be found using the following formula:
Let's rearrange the formula to find the volume, .
The volume can be found by dividing the mass by the density. The mass of the chloroform is 5 grams and the density is 1.49 grams per milliliter. Therefore,
Substitute the values into the formula.
Divide. When we divide, the grams, or g, in the numerator and denominator will cancel out.
The volume of 5 grams of chloroform is 3.3557047 milliliters