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3 years ago

What is the density of a gas with a molar mass of 28.26 grams per mole at 3.510 ATM in 237 Kelvin

Chemistry

1 answer:

Vikki [24]3 years ago

6 0

<h3><u>Answer;</u></h3>

= 5.1 g/L

<h3><u>Explanation;</u></h3>

Using the equation;

PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.

Number of moles is 1 since one mole has a mass equivalent to the molar mass.

Therefore; We can find the volume and thus get the density.

<em>V = nRT/P</em>

<em> = (1 × 0.08206 × 237)/3.510</em>

<em> = 5.5408 L</em>

<em>Hence; Density = mass/volume </em>

<em> = 28.26 g/5.5408 L</em>

<em> = 5.1 g/L</em>

<em>The Density is 5.1 g/L or 0.005 g/cm³</em>

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What is the density of a gas with a molar mass of 28.26 grams per mole at 3.510 ATM in 237 Kelvin​

What is the density of a gas with a molar mass of 28.26 grams per mole at 3.510 ATM in 237 Kelvin