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3 years ago

What are the coordinates of the point that is one half the distance between A(−3, −5) and B(2, 7)?

Mathematics

1 answer:

Olenka [21]3 years ago

3 0

Answer:

$(\frac{-1}{2},1)$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

Step 1: Define

A (-3, -5)

B (2, 7)

Step 2: Find midpoint

Substitute: $(\frac{-3+2}{2},\frac{-5+7}{2})$
Add: $(\frac{-1}{2},\frac{2}{2})$
Divide: $(\frac{-1}{2},1)$

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Evaluating the Six Trigonometric Function Question attached

ziro4ka [17]

If tan theta is -1, we know immediately that theta is in either Quadrant II or Q IV. We need to focus on Q IV due to the restrictions on theta.

Because tan theta is -1, the ray representing theta makes a 45 degree angle with the horiz axis, and a 45 degree angle with the negative vert. axis. Thus the hypotenuse, by the Pythagorean Theorem, tells us that the hyp is sqrt(2).
Thus, the cosine of theta is adj / hyp, or +1 / sqrt(2), or [sqrt(2)]/2

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6 0

3 years ago

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jonny [76]

Answer:

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Step-by-step explanation:

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4 0

3 years ago

What are the next three terms in the sequence -27, -19, -11, -3, 5, ...?

ddd [48]

Answer:

13, 21, 29

Step-by-step explanation:

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3 0

3 years ago

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Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a

Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = $\frac{1}{6}$

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

$E(X)=\sum x\cdot P(X=x)$

Compute the expected monetary value of a single roll as follows:

$E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17$

Thus, the expected monetary value of a single roll is $1.17.

7 0

3 years ago

Solve the equation 1.5y < -6.75

finlep [7]

1.5y < -6.75

First, divide both sides by '1.5'.
$\frac{-6.5}{1.5}$
Second, since 4.5 × 1.5 = 6.5, simplify the fraction to '-4.5'
$y \ \textless \ -4.5$

Answer: y < -4.5

7 0

3 years ago