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seraphim [82]
3 years ago
8

Larry uses 9 eggs to fill 3 baskets. If each basket has the same number of eggs, how many eggs will there be in 30 baskets?

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
7 0

Answer:

90 eggs

Step-by-step explanation:

9/3=x/30

3x=270

×90

Anna007 [38]3 years ago
4 0

Answer:

90 eggs

Step-by-step explanation:

Mark me Brainllest

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Ray Of Light [21]
To find the first blank, just replace x in the equation with 12 and solve.
a(12) = 50 - 1.25(12) = your answer for blank 1

For blank 2: because x represents the number of apps on her phone, and x is given 12 for this problem, she bought 12 apps.

For blank 3: You would mention how many apps she got twice, so not the first option or the third option. It should be the answer from the first blank because the equation represents how much money is in her account.
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3 years ago
Express -23 in the form bi where b is a real number TIME SENSITIVE
balu736 [363]

Answer:

A

Step-by-step explanation:

i stands for square root of negative 1. If you multiple i and square root of 23 you will end up with the original

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3 years ago
Melinie 1 tom2 and admission 3<br> Help
Len [333]

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3 years ago
A population of geese grow in such a way that each generation is simply 2.2 times the previous generation. There were 3 geese in
lapo4ka [179]
First generation: 3

Second generation: 3\times2.2

Third generation: 3\times2.2\times2.2=3\times2.2^2

Fourth generation: 3\times2.2\times2.2\times2.2=3\times2.2^3

And so on. The general formula for the nth generation is 3\times2.2^{n-1}. So by the 15th generation, you should expect around 3\times2.2^{15-1}\approx186655 geese.
5 0
3 years ago
Read 2 more answers
How do you do this problem? I need to know how you found the answer.
Alexxandr [17]

to get the equation of a line, we simply need two points, say for the Red one ... notice in the graph the lines passes through (0,2) and (-1,6), so let's use those


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{-1-0}\implies \cfrac{4}{-1}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-4(x-0) \\\\\\ y-2=-4x\implies \blacktriangleright y=-4x+2 \blacktriangleleft


now, for the Blue one, say let's use hmmm it passes through (0,2) and (1.6)


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{1-0}\implies \cfrac{4}{1}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=4(x-0) \\\\\\ y-2=4x\implies \blacktriangleright y=4x+2 \blacktriangleleft

3 0
3 years ago
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