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Alekssandra [29.7K]
2 years ago
5

Quadrilaterals WXYZ and W"X"Y"Z"are similar. Identify the type of reflection

Mathematics
1 answer:
Anna71 [15]2 years ago
5 0

Answer:

B) To obtain quadrilateral W'X'Y"Z" quadrilateral WXYZ is reflected across

the x-axis and dilated with a scale factor of 1/2

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, rotation, translation and dilation.

If a point A(x, y) is reflected across the x axis the new point is at A'(x, -y)

Dilation is the enlargement or reduction in the size of a figure by a scale factor. If a point A(x, y) is dilated by a scale factor of k about the center of origin, the new point is at A'(kx, ky).

The vertex of Quadrilaterals WXYZ is at W(-6, 8), X(-2, 8), Y(-2, 2), Z(-6, 8) while the vertex of Quadrilaterals W"X"Y"Z" is at W"(-3, -4), X"(-2, -4), Y"(-1, -1), Z"(-3, -4)

If quadrilateral WXYZ is reflected across  the x-axis, the new coordinates would be at W'(-6, -), X'(-2, -8), Y'(-2, -2), Z'(-6, -8). If the quadrilateral is then dilated with a scale factor of 1/2, the new point is at W"(-3, -4), X"(-2, -4), Y"(-1, -1), Z"(-3, -4)

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Answer: it took him 0.075 seconds lesser

Step-by-step explanation:

In his first heat, his time was 2.45 seconds greater than his friend's record time. In his second heat, his time was 2 3/8 seconds greater than his friend's record time. Converting 2 3/8 seconds to decimal, it becomes 2.375 seconds

Therefore, he was fastest in the second heat.

The difference between the time he used to run in the second heat than in the first heat is

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Step-by-step explanation:

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Answer:

t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604  

p_v =2*P(t_{(88)}>2.604)=0.0108

So the p value is a very low value and using any significance level for given \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

Step-by-step explanation:

Data given and notation

\bar X_{1}=9.1 represent the mean for the sample 1

\bar X_{2}=8 represent the mean for the sample 2

s_{1}=1.9 represent the sample standard deviation for the sample 1

s_{2}=2.1 represent the sample standard deviation for the sample 2

n_{1}=40 sample size for the group 1

n_{2}=50 sample size for the group 2

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean are different , the system of hypothesis would be:

Null hypothesis:\mu_{1} = \mu_{2}

Alternative hypothesis:\mu_{1} \neq \mu_{2}

If we analyze the size for the samples both are higher than 30 and the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We can replace in formula (1) the results obtained like this:

t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604  

Statistical decision

The first step is calculate the degrees of freedom, on this case:

df=n_{1}+n_{2}-2=40+50-2=88

Since is a bilateral test the p value would be:

p_v =2*P(t_{(88)}>2.604)=0.0108

So the p value is a very low value and using any significance level for given \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

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Your answer would be 62
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