From the information given, each batch of cookies requires 1/6 of a bag of flour.
So how many batches can be gotten from 5/6 of the bag of flour?
We form an equation
1batch = 1/6
x batches = 5/6
Where x is the number of batches from 5/6 bag of flour.
Cross multiplying this equation we get:
x * 1/6 = 1 * 5/6
simplify it:
x * 0.16 = 1 * 0.83
x = 1 * 0.83 / 0.16
x = 0.83 / 0.16
x = 5.2
Therefore factory made approximately 5 batches of cookies yesterday.
Given:
The data values are
11, 12, 10, 7, 9, 18
To find:
The median, lowest value, greatest value, lower quartile, upper quartile, interquartile range.
Solution:
We have,
11, 12, 10, 7, 9, 18
Arrange the data values in ascending order.
7, 9, 10, 11, 12, 18
Divide the data in two equal parts.
(7, 9, 10), (11, 12, 18)
Divide each parenthesis in 2 equal parts.
(7), 9, (10), (11), 12, (18)
Now,
Median = 
= 
= 
Lowest value = 7
Greatest value = 18
Lower quartile = 9
Upper quartile = 12
Interquartile range (IQR) = Upper quartile - Lower quartile
= 12 - 9
= 3
Therefore, median is 10.5, lowest value is 7, greatest value is 18, lower quartile 9, upper quartile 12 and interquartile range is 3.
I think 50 oz less
hope it helps
You want to find the area left over after the pool is built, so subtract the area of the pool from the area of the yard.
Area of Yard= Base x Height = 14x*19x = 266x^2
Area of Circle= Pi x Radius^2 = (6x)^2*pi = 36x^2*pi
Now subtract the two areas:
266x^2-(36^2*pi)
266x^2-36x^2*pi
Take 2x^2 as a common factor:
2x^2(133-18pi)
D: <span>2x^2(133-18pi)
Hope this helps :)</span>
Step-by-step explanation:
31/2×5/23 (use reciprocal)
31×5=155
155÷46=3.369565217
155/46
3 and 17/46
