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vodka [1.7K]
4 years ago
5

They confessed their guilt.​

Physics
2 answers:
Kipish [7]4 years ago
7 0
That’s not a question???? What’s the question
nika2105 [10]4 years ago
5 0

Answer:

heyyy

May I Know the full question

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I am looking for this answer :Which shows a correct order of steps in the scientific method?
ELEN [110]

Answer:

Explanation:

make observations, draw conclusions, develop a hypothesis, analyze data.

6 0
3 years ago
55N of force are applied onto a table, but the force of friction is 8N. What is the net force acting on the table? Please explai
nirvana33 [79]

Answer:

get a tutor or something to help man

Explanation:

8 0
3 years ago
The two hot-air balloons in the drawing are 48.2 and 61.0 m above the ground. A person in the left balloon observes that the rig
Lynna [10]

Answer:

x = 54.15 meters between the balloons horizontally.

Explanation:

Hence, vertical distance between balloons is 12.8 meters.

y= 61-48.2  = 12.2 m

A right-angle triangle is formed with,

angle θ = 13.3 degrees

opposite (y) = 12.8

adjacent (x) = ?

tan\theta = \dfrac{y}{x}

Now by putting the values in the above equation.

tan13^{\circ}=\dfrac{12.8}{x}

x=\dfrac{12.8}{tan13^{\circ}}

x = 54.15 meters between the balloons horizontally.

8 0
3 years ago
If 6.24×10¹⁸ electron pass through a wire in 1s how many pass through it during a time interval of 2hr, 47min and 10s
levacccp [35]
Answer = 6.24x10^18 x ((2 x 3600) + (47 x 60) + 10)
3 0
3 years ago
In a certain clock, a pendulum of length L1 has a period T1 = 0.95s. The length of the pendulum
gulaghasi [49]

Answer:

Ratio of length will be \frac{L_2}{L_1}=1.108

Explanation:

We have given time period of the pendulum when length is L_1 is T_1=0.95sec

And when length is L_2 time period T_2=1sec

We know that time period is given by

T=2\pi \sqrt{\frac{L}{g}}

So 0.95=2\pi \sqrt{\frac{L_1}{g}}----eqn 1

And 1=2\pi \sqrt{\frac{L_2}{g}}-------eqn 2

Dividing eqn 2 by eqn 1

\frac{1}{0.95}=\sqrt{\frac{L_2}{L_1}}

Squaring both side

\frac{L_2}{L_1}=1.108

8 0
4 years ago
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