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Ilya [14]
3 years ago
14

The two hot-air balloons in the drawing are 48.2 and 61.0 m above the ground. A person in the left balloon observes that the rig

ht balloon is 13.3° above the horizontal. What is the horizontal distance x between the two balloons?

Physics
1 answer:
Lynna [10]3 years ago
8 0

Answer:

x = 54.15 meters between the balloons horizontally.

Explanation:

Hence, vertical distance between balloons is 12.8 meters.

y= 61-48.2  = 12.2 m

A right-angle triangle is formed with,

angle θ = 13.3 degrees

opposite (y) = 12.8

adjacent (x) = ?

tan\theta = \dfrac{y}{x}

Now by putting the values in the above equation.

tan13^{\circ}=\dfrac{12.8}{x}

x=\dfrac{12.8}{tan13^{\circ}}

x = 54.15 meters between the balloons horizontally.

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Answer: - 452.088joule

Explanation:

Given the following :

Mass of water = 12g

Change in temperature(Dt) = (11 - 20)°C = - 9°C

Specific heats capacity of water(c) = 4.186j/g°C

Q = mcDt

Where Q = quantity of heat

Q = 12g × 4.186j/g°C × - 9°C

Q = - 452.088joule

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Are white clouds transparent opaque or translucent
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4 years ago
What is meant by angular frequency?
andrew11 [14]

measures angular displacement per unit time. Its units are therefore degrees (or radians) per second.

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3 years ago
If she can throw each rock with a speed of 7.5 m/s relative to the ground, causing the wagon to move, how many rocks must she th
Stels [109]

Complete question:

A child sits in a wagon with a pile of 0.64-kg rocks. If she can throw each rock with a speed of 7.5 m/s relative to the ground, causing the wagon to move, how many rocks must she throw per minute to maintain a constant average speed against a 3.9-N force of friction

Answer:

The number of rocks per minutes thrown is 49 rocks/min

Explanation:

Given;

mass of the rock, m = 0.64 kg

speed of the rock, v = 7.5 m/s

frictional force, f_k = 3.9 N

For an object to move at a constant speed, the applied force must be equal to the frictional force.

f_k = N(F_a)\\\\f_k = N(\frac{mv}{t})\\\\f_k = \frac{N}{t} (mv)\\\\\frac{N}{t} = \frac{f_k}{mv}

where;

F_a is the applied force

N/t is the number of rocks per minutes thrown

Substitute the given parameters;

\frac{N}{t} = \frac{f_k}{mv}\\\\ \frac{N}{t} = \frac{3.9}{0.64*7.5}\\\\ \frac{N}{t} = 0.8125 \ \frac{rocks}{second} * \frac{60 \ seconds}{1 \ min} = 48.75 \ \frac{rocks}{min}  \

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5 0
3 years ago
A twin-sized air mattress used for camping has dimensions of 100 cm by 194 cm by 14 cm when blown up. The weight of the mattress
Paul [167]

Answer:

2625.156\ \text{N}

Explanation:

Dimensions of mattress 100 cm by 194 cm by 14 cm

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g = Acceleration due to gravity = 9.81\ \text{m/s}^2

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Weight of water displaced is equal to the buoyant force

Mass of water

m=\rho V\\\Rightarrow m=1000\times 0.2716\\\Rightarrow m=271.6\ \text{kg}

Mass of person would be

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Weight of the person would be

w=m_pg\\\Rightarrow w=267.6\times 9.81\\\Rightarrow w=2625.156\ \text{N}

The air mattress could hold a person that weighs up to 2625.156\ \text{N}.

8 0
3 years ago
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