- Mass of the car (m) = 2000 Kg
- Initial velocity (u) = 15 m/s
- Force (F) = 10000 N
- Time (t) = 3 s
- Let the acceleration be a.
- By using the formula, F = ma, we get,
- 10000 N = 2000 Kg × a
- or, a = 10000 N ÷ 2000 Kg
- or, a = 5 m/s^2
- Let the final velocity be v.
- By using the formula, v = u + at, we get,
- v = 15 m/s + 5 m/s^2 × 3 s
- or, v = 15 m/s + 15 m/s
- or, v = 30 m/s
<u>Answer</u><u>:</u>
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Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer:
-450 m/s
Explanation:
Momentum is conserved.
p₀ = p
0 = (1.5 kg) (1.5 m/s) + (0.005 kg) v
v = -450 m/s
Work=applied Force x distance
= 1275 x 26
=33150 Joules
The interaction between two like-charged objects is repulsive. ... Positively charged objects and neutral objects attract each other; and negatively charged objects and neutral objects attract each other.