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2 years ago

I am looking for this answer :Which shows a correct order of steps in the scientific method?

Physics

1 answer:

ELEN [110]2 years ago

6 0

Answer:

Explanation:

make observations, draw conclusions, develop a hypothesis, analyze data.

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How long does it take someone to run 8 miles if they are running at a speed of 7 km/hr?

ZanzabumX [31]

Answer:

1.84 hours or 110.4 minutes

Explanation:

8 miles 1.61 km 1 hr

------------ x ----------------- x -------------- = 1.84 hours or 110.4 minutes

1 mile 7 km

7 0

2 years ago

An emf source of 6.0V is connected to a purely resistive lamp and a current of 2.0 amperes flows. All the wires are resistance-f

IgorC [24]

Resistance = (voltage) / (current)

Resistance = (6.0 v) / (2.0 A)

Resistance = 3.0 ohms

7 0

2 years ago

An object with a mass M = 250 g is at rest on a plane that makes an angle θ = 30 o above the horizontal. The coefficient of kine

liubo4ka [24]

Answer:

v = 79.2 m/s

Solution:

As per the question:

Mass of the object, m = 250 g = 0.250 kg

Angle, $\theta = 30^{\circ}$

Coefficient of kinetic friction, $\mu_{k} = 0.100$

Mass attached to the string, m = 0.200 kg

Distance, d = 30 cm = 0.03 m

Now,

The tension in the string is given by:

$Mgsin\theta + \mu_{k}Mgcos\theta + Ma = T$ (1)

Also

T = m(g + a)

Thus eqn (1) can be written as:

$Mgsin\theta + \mu_{k}Mgcos\theta + Ma = m(g - a)$

$Mgsin\theta + \mu_{k}Mgcos\theta + Ma = mg + ma$

$mg - Mgsin\theta - \mu_{k}Mgcos\theta = (M - m)a$

$a = \frac{0.2\times 9.8 - 0.250\times 9.8\times sin30^{\circ} - 0.1\times 0.250\times 9.8\times cos30^{\circ}}{0.250 - 0.200}$

$a = 10.45\ m/s^{2}$

Now, the speed is given by the third eqn of motion with initial velocity being zero:

$v^{2} = u^{2} + 2ad$

where

u = initial velocity = 0

Thus

$v = \sqrt{2ad}$

$v = \sqrt{2\times 10.45\times 0.03} = 0.792\ m/s$

3 0

2 years ago

A 50kg chandelier hangs from a ceiling suspended by a cable.

babunello [35]

Answer:

The tension force has a magnitude of 490 N, and acts vertically upward

Explanation:

The complete question is:

A 50kg chandelier hangs from a ceiling suspended by a cable. What is the Tension (magnitude and direction of the force) in the cable?

ANS:

Tension is the force applied axially by rope, chain, cable, rod, etc, as a reaction force. The direction of tension is always towards the support. Since, the support here, is ceiling.

Therefore, the direction of tension force will be vertically upward.

Since the chandelier is hanging stationary, without any motion. Thus, there must not be any unbalanced force applied on it.

Hence, the tension force must be equal to the weight of chandelier.

Tension Force = Weight of Chandelier

T = W = mg

T = (50 kg)(9.8 m/s²)

T = 490 N

Thus, the tension force has a magnitude of 490 N, and acts vertically upward

6 0

2 years ago

Two cars started at the same position and were driven through a city using different streets. The red car traveled north 2 miles

inysia [295]

Answer:

The green car traveled a shorter distance, but the displacement of the cars was equal.

Explanation:

4 0

2 years ago