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LUCKY_DIMON [66]
3 years ago
10

Could someone please help me with this​

Mathematics
1 answer:
horrorfan [7]3 years ago
4 0

Answer:

F

Step-by-step explanation:

F doesn't represent a function because -1 and 2 have multiple outputs. A function is when an input only has one output. F is not a function.

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Read 2 more answers
Which relation below does NOT represent a function?
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I think it is the bottom left
7 0
3 years ago
For each of the following, select the correct words from the word bank to complete each statement.
Anuta_ua [19.1K]

Answer:

Angles opposite one another that share a vertex are called <u>vertical</u> angles.

When one of these angles undergo a rigid transformation so that it fits exactly over the other, we know that the two angles are <u>congruent</u>

When two parallel lines are crossed by another line called the <u>transversal</u> the angles created inside the parallel lines but on opposite sides of the crossing lines are called <u>alternate</u> <u>interior</u> angles. Angles of this type have the same measurement as one another. Two figures are <u>similar</u> if one can fit exactly over the other after rigid transformations and dilations

Step-by-step explanation:

Vertically opposite angles are always equal (congruent)

The transversal line is the line that crosses two or more parallel lines

Alternate interior angles formed by two parallel lines crossed by a common transversal, are congruent

Two plane geometric figures are similar if they their corresponding interior angles are congruent

4 0
3 years ago
Which expression is equivalent to \frac{10q^5w^7}{2w^3}.\ \frac{4\left(q6\right)^2}{w^{-5}} for all values of q and w where the
mestny [16]

Answer:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

Step-by-step explanation:

Given

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Required

Determine the equivalent expression

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Simplify the first fraction

\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Apply law of indices on the first fraction;

5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}

\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}

Apply law of indices:

5q^5w^4*4\left(q^6\right)^2 * w^{5}

Evaluate the bracket

5q^5w^4*4 * q^{12} * w^{5}

Collect Like Terms

5*4q^5* q^{12}*w^4  * w^{5}

20q^5* q^{12}*w^4  * w^{5}

20q^{5+12}*w^{4+5}

20q^{17}w^9

Hence:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

7 0
3 years ago
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