Answer:
1/12
Step-by-step explanation:
first we have to find all the possibilities of getting a sum of 3 or less: 1+1 or 1+2 and we count the second combination 2 times because the numbers can be on either of the dices so we have a total of 3 possibilities. all the possible pairimg of dice are 6*6=36 because each dice has 6 sides and we can get either of them. so the probability would be the chance of getting a sum of 3 or less divided by all the diff combination which equals 3/36 or 1/12 which is roughly around 8.3%
The number of possible combinations is given by
... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations
_____
There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.
1. 5.50 + 0.15 * 45 = 12.25
2. 4 + 0.20 * 45 = 13
So the first option is slightly better, you can save 13-12.25= $0.75.
Answer:
Step-by-step explanation:
-b -b +5
= -2b + 5
Answer:
4 and 6
Step-by-step explanation:
4 + 6 = 10
4 x 6 = 24
