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jekas [21]
1 year ago
11

A construction worker earns an average bi-weekly net pay of $1,764.00. Which compound inequality correctly shows the amount of m

oney, t, the worker can spend if the monthly budget for food is between 10% and 20%?
$176.40 ≤ t ≤ $352.80
$352.80 ≤ t ≤ $706.50
$382.20 ≤ t ≤ $764.40
$420.42 ≤ t ≤ $573.30
Mathematics
2 answers:
Irina-Kira [14]1 year ago
6 0

Answer:

$382.20 ≤ t ≤ $764.40

Step-by-step explanation:

Hello, so first we would need to convert bi-weekly pay to monthly income.

First we would times $1,764.00 by 26

1764.00 × 26 = 45864

Then we would divide 45864 by 12

45864 ÷ 12 = 3822.

Then we calculate how much the worker can spend  if their monthly budget for food is in between 10% and 20%

3822 ×  10% = 382.20

3822 × 20% = 764.40

So, we can see the correct answer is $382.20 ≤ t ≤ $764.40.

denpristay [2]1 year ago
4 0

The compound inequality is $176.40 ≤ t ≤ $352.80 if a construction worker earns an average bi-weekly net pay of $1,764.00 option (A) Is correct.

<h3>What is inequality?</h3>

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

It is given that:

A construction worker earns an average bi-weekly net pay of $1,764.00.

= 10% of 1764

= (10/100)1764

= $176.4

= 20% of 1764

= (20/100)1764

= $352.8

Inequality will be: $176.40 ≤ t ≤ $352.80

Thus, the compound inequality is $176.40 ≤ t ≤ $352.80 if a construction worker earns an average bi-weekly net pay of $1,764.00 option (A) Is correct.

Learn more about inequality here:

brainly.com/question/19491153

#SPJ2

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