Question

A construction worker earns an average bi-weekly net pay of $1,764.00. Which compound inequality correctly shows the amount of money, t, the worker can spend if the monthly budget for food is between 10% and 20%?
$176.40 ≤ t ≤ $352.80
$352.80 ≤ t ≤ $706.50
$382.20 ≤ t ≤ $764.40
$420.42 ≤ t ≤ $573.30

Answer 1

Answer:

$382.20 ≤ t ≤ $764.40

Step-by-step explanation:

Hello, so first we would need to convert bi-weekly pay to monthly income.

First we would times $1,764.00 by 26

1764.00 × 26 = 45864

Then we would divide 45864 by 12

45864 ÷ 12 = 3822.

Then we calculate how much the worker can spend  if their monthly budget for food is in between 10% and 20%

3822 ×  10% = 382.20

3822 × 20% = 764.40

So, we can see the correct answer is $382.20 ≤ t ≤ $764.40.

Answer 2

The compound inequality is $176.40 ≤ t ≤ $352.80 if a construction worker earns an average bi-weekly net pay of $1,764.00 option (A) Is correct.

What is inequality?

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

It is given that:

A construction worker earns an average bi-weekly net pay of $1,764.00.

= 10% of 1764

= (10/100)1764

= $176.4

= 20% of 1764

= (20/100)1764

= $352.8

Inequality will be: $176.40 ≤ t ≤ $352.80

Thus, the compound inequality is $176.40 ≤ t ≤ $352.80 if a construction worker earns an average bi-weekly net pay of $1,764.00 option (A) Is correct.

Learn more about inequality here:

brainly.com/question/19491153

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