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3 years ago

5

It is found experimentally that the electric field in a certain region of Earth's atmosphere is directed vertically down. At an

altitude of 390 m the field has magnitude 60.0 N/C. At an altitude of 240 m, the magnitude is 100 N/C. Find the net amount of charge contained in a cube 150 m on edge, with horizontal faces at altitudes of 240 and 390 m. Neglect the curvature of Earth.

1 answer:

Maru [420]3 years ago

5 0

Answer:

$q=7.965*10^-^6C$

Explanation:

From the question we are told that

Altitude of $d_1 390m$

Magnitude $M_1=60.0 N/C$

Altitude of $d_2=240 m$

Magnitude is $M_2= 100 N/C$

Distance of cube $d_c=150 m$

Generally the flux $\phi$ is mathematical given as

$\phi=60(150)^2cos180+100(150)^2*cos0$

$\phi=-9*10^5$

Generally Quantity of charge q is mathematically given as

$q=\varepsilon _0 *\phi$

$q=8.85*10^-^1^2 *9*10^5$

$q=7.965*10^-^6C$

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