<em>The y-intercept of a position-time graph of an object gives the average velocity of the object is False.</em>
<u>Answer:</u> <em>False.
</em>
<u>Explanation:</u>
The initial position of the object can be obtained by calculating the Y intercept of a position-time graph. In a position-time graph, the independent variable is time and dependent variable is position. Y axis is the position axis and x axis is the time axis.
The equation of the graph is given by
. m is the slope of the graph and c is the y intercept. When a particle starts from the origin its y intercept is zero.
The nature of the graph gives us an idea about velocity. When the velocity is positive, the position- time graph has positive slope and when the velocity is positive the graph has negative slope.
Answer: a) Cnew=Cinitial ; b) λouter new= 2*λ outer initial
Explanation: In order to explain this question we have to take into account the expression of teh cylinder capacitor given by:
C/L= (2*π*εo)/ln (b/a)= where b and a are the outer and inner radius, respectively. L is the length of the capacitor.
As you can se this formule depents of geometrical characateristics of the capacitor.
The capacitance is the same after change the densities of charge.
On the other hand,
The new charge in each cylinder ( inner and outer) is determined
The new potential is 2 times the initial one so
V new= 2* Vinitial
Also we know that
Vnew= Q/C= λnew*L/C; C= constant
using this formule and considering that V new is doubled then the charge per one meter length, is also doubled .
This is as follow:
Vnew= λnew*L/C=
λnew = (2*Vinitial)* C/L= 2 (λ initial)
Then λouter new = 2* λouter initial
I think c I’m not sure tho
Add force to unbalance the forces