All categories

2 years ago

What is the surface tension of water? of rubbing alcohol? was your prediction correct or incorrect?

Physics

1 answer:

kompoz [17]2 years ago

6 0

Rubbing water (isopropyl alcohol) has lesser surface tension than that water.

Water possesses a surface tension of 72 dynes/cm.

Whereas rubbing alcohol has a surface tension of 23 dynes/cm.

<h3>what is surface tension?</h3>

Surface tension is the propensity of liquid surfaces at rest to shrink to the smallest possible surface area.

Because the atoms on the outside of the molecules (often hydrogens) lack strong hydrogen bonding capabilities, most organic liquids have very low surface tensions. Because isopropanol contains just 28%, OH and the remainder is CH or CH3, the linkages that hold a droplet together are few and far between.

The only substance with a higher surface tension than water is liquid mercury (450 dyne/cm).

Learn more about surface tension here:

brainly.com/question/19390213

#SPJ4

You might be interested in

what was the acceleration of the cart with Low fan speed cm/s squared? what was the acceleration of the cart with medium fan spe

ArbitrLikvidat [17]

Explanation:

The attached figure shows data for the cart speed, distance and time.

For low fan speed,

Distance, d = 500 cm

Time, t = 7.4 s

Average velocity,

$v=\dfrac{d}{t}\\\\v=\dfrac{500}{7.4}\\\\v=67.56\ cm/s$

Acceleration,

$a=\dfrac{v}{t}\\\\a=\dfrac{67.56}{7.4}\\\\a=9.12\ cm/s^2$

For medium fan speed,

Distance, d = 500 cm

Time, t = 6.4 s

Average velocity,

$v=\dfrac{d}{t}\\\\v=\dfrac{500}{6.4}\\\\v=78.12\ cm/s$

Acceleration,

$a=\dfrac{v}{t}\\\\a=\dfrac{78.12}{6.4}\\\\a=12.2\ cm/s^2$

For high fan speed,

Distance, d = 500 cm

Time, t = 5.6 s

Average velocity,

$v=\dfrac{d}{t}\\\\v=\dfrac{500}{5.6}\\\\v=89.28\ cm/s$

Acceleration,

$a=\dfrac{v}{t}\\\\a=\dfrac{89.28}{5.6}\\\\a=15.94\ cm/s^2$

Hence, this is the required solution.

8 0

3 years ago

Read 2 more answers

The summer camps had a field trip from the campus to Fragrance Hill. They traveled at an average speed of 65 km/h in the first 2

ludmilkaskok [199]

Answer:

Explanation:

They traveled this distance in 2 parts, essentially. Part 1 had an average speed for a certain number of hours, part 2 had an average speed for a certain number of hours, and those 2 parts taken together took them a distance of 364 km. In equation form, that looks like this:

km/hr part 1 + km/hr part 2 = 364 km

Now we need to find each part on the left side of that equation. Part 1 first:

We traveled 65 km/hr for 2 hours, so that took us

$65\frac{km}{hr}*2hr$ and canceling out the hour label, we have that in part 1 we got