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3 years ago

Which is an example of a mixture made of parts that can easily be separated?

Physics

1 answer:

Gemiola [76]3 years ago

8 0

Answer

sand and water is an example of a mixture made of parts that can easily be separated

Explatnation

mixture is a material which is formed by mixing two or more different types of materials. No chemical reaction occurs.During combination of two or more type of material to form a mixture.

Example of mixture are

oil and water

sand and water

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A bee loaded with pollen flies in a circular path at a constant speed of 3.20 m/s. If the mass of the bee is 133 mg and the radi

BaLLatris [955]

<h3><u>Answer;</u></h3>

Centripetal acceleration = 0.931 m/s²

Centripetal force = = 1.234 × 10^-4 Newtons

<h3><u>Explanation;</u></h3>

Centripetal acceleration is given by the formula v²/r, where r is the radius of the circular path and v is the velocity of a body;

Centripetal acc = 3.2²/11

= 0.931 m/s²

Centripetal force is a force that acts on an object or a body in circular path and is directed towards the center of the circular path.

Centripetal force is given by the formula;

mv²/r ; where m is the mass of the body, r is the radius of the circular path and v is the velocity of a body;

mass = 33 mg or 1.33 × 10^-6 kg, velocity = 3.20 m/s and r = 11 m

Therefore;

Centripetal force = (1.33 ×10^-6 × 3.1²)/ 11

= 1.234 × 10^-4 Newtons

8 0

3 years ago

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How to get a + b on a graph

Nataly [62]

The first positively essential requirement is that
you absolutely have to know what 'a' and 'b' are.

I have no clue, so this is as far as I can go.

3 0

3 years ago

Two charges (q1 = 3.8*10-6C, q2 = 3.2*10-6C) are separated by a distance of d = 3.25 m. Consider q1 to be located at the origin.

Sergio039 [100]

Answer:

The distance is 1.69 m.

Explanation:

Given that,

First charge $q_{1}= 3.8\times10^{-6}\ C$

Second charge $q_{2}=3.2\times10^{-6}\ C$

Distance = 3.25 m

We need to calculate the distance

Using formula of electric field

$E_{1}=E_{2}$

$\dfrac{kq_{1}}{x^2}=\dfrac{kq_{2}}{(d-x)^2}$

$\dfrac{q_{1}}{q_{2}}=\dfrac{(x)^2}{(d-x)^2}$

$\sqrt{\dfrac{q_{1}}{q_{2}}}=\dfrac{x}{d-x}$

$x=(d-x)\times\sqrt{\dfrac{q_{1}}{q_{2}}}$

Put the value into the formula

$x=(3.25-x)\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}$

$x+x\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}=3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}$

$x(1+\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}})=3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}$

$x=\dfrac{3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}}{(1+\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}})}$

$x=1.69\ m$

Hence, The distance is 1.69 m.

5 0

3 years ago

Consider a hydrogen atom in the n = 1 state. The atom is placed in a uniform B field of magnitude 2.5 T. Calculate the energy di

dlinn [17]

Answer:

$E=29\times 10^{-5}eV$

Explanation:

For n-=1 state hydrogen energy level is split into three componets in the presence of external magnetic field. The energies are,

$E^{+}=E+\mu B$ ,

$E^{-}=E-\mu B$ ,

$E^{0}=E$

Here, E is the energy in the absence of electric field.

And

$E^{+} and E^{-}$ are the highest and the lowest energies.

The difference of these energies

$\Delta E=2\mu B$

$\mu=9.3\times 10^{-24}J/T$ is known as Bohr's magneton.

B=2.5 T,

Therefore,

$\Delta E=2(9.3\times 10^{-24}J/T)\times 2.5 T\\\Delta E=46.5\times 10^{-24}J$

Now,

$Delta E=46.5\times 10^{-24}J(\frac{1eV}{1.6\times 10^{-9}J } )\\Delta E=29.05\times 10^{-5}eV\\Delta E\simeq29\times 10^{-5}eV$

Therefore, the energy difference between highest and lowest energy levels in presence of magnetic field is $E=29\times 10^{-5}eV$

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3 years ago

In the equation for the gravitational force between two objects, which quantity must be squared?

Trava [24]

The distance quantity/ measurement must be squared.

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3 years ago

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