Answer:
Force on front axle = 6392.85 N
Force on rear axle = 8616.45 N
Explanation:
As we know that the weight of the car is balanced by the normal force on the front wheel and rear wheels
Now we know that
now we know that distance between the axis is 2.70 m and centre of mass is 1.15 m behind front axle
so we can write torque balance about its center of mass
now from above equation
now we have
now the other force is given as
M=2.45 because you multiply out the equation on the right and divide by 10
<span>Acceleration is the change in velocity divided by time.
We can find acceleration a, by the following formula
a=v-u/t
where,
v is the final velocity (in this question v=8.0 m/s)
u is the initial velocity (since the hamster starts from rest, u=0)
t is the time taken (i,e 3.0 second)
now by applying the formula we have,
a = 8.0 - 0 / 3
= 8 / 3
= 2.65 m/s</span>²<span>
The acceleration is 2.65 meters per second squared</span>
