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GuDViN [60]
3 years ago
5

2|3x – 5= 10 How do I solve

Mathematics
1 answer:
VLD [36.1K]3 years ago
3 0

Answer: 45/2

Step-by-step explanation:

Step 1: Add 5 to both sides.

2/3x−5+5=10+5

2/3x=15

Step 2: Multiply both sides by 3/2.

(3/2)*(2/3x)=(3/2)*(15)

x=45/2

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8 0
3 years ago
Read 2 more answers
Solve -7/2=-28 please solve and show work
Assoli18 [71]

Step-by-step explanation:

-7/2 = -28

-7 = -28 × 2

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5 0
3 years ago
A square has a side that measures 5.5 units. What is the area of a circle with a circumference that equals the perimeter of the
Alexeev081 [22]

Answer:

Answer choice A) About 38.47 square units

Step-by-step explanation:

Since all four sides of a square have the same length, the perimeter of a square is just 4 times one of the side lengths. The perimeter of the square and therefore the circumference of the circle is 5.5*4=22. The circumference of a circle is 2 times the radius multiplied by pi. The radius of this circle is therefore:

\dfrac{22}{2\pi}\approx 3.503

Since the area of a circle is \pi r^2, the area of this circle is:

\pi \cdot 3.503^2= 3.14\cdot 12.271\approx 38.47

Hope this helps!

4 0
3 years ago
Which expression is equivalent to the one below?
Anarel [89]

Answer:

B

Step-by-step explanation:

Start by breaking down the equation

-1/2 x 10 = -5

-1/2x1/4=-1/4

Then combine your answer

-5=1/8

8 0
3 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
4 years ago
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