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Sati [7]
3 years ago
7

I will give brainliest to whoever can answer this, I can’t figure out how I’m supposed to use Pascal’s Triangle to find my answe

r, I’ve been trying for hours, please help. Write out the coefficient of x^3 in the expansion of: (6-2x)^7
Mathematics
1 answer:
mart [117]3 years ago
3 0

Answer:

so, x^3 which is ×03 so basically 6 -2×2×7÷3= is 33.3

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What is w for -3w = -7(w+1)
Alchen [17]
-3w= -7w-7 =
-3w+7w = -7w+7w - 7 =
4w= -7
4w/4 = -7/4 =
w = -7/4

3 0
3 years ago
⭐ Question 3
mash [69]

Answer:

1/10

Step-by-step explanation:

Because there are 10 markers and only one is yellow. so you have a one in ten chance to pull a yellow marker.

<em>Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Also remember to rate answers to help other students, While leaving thanks to answers that help you. Have a great day!</em>

8 0
3 years ago
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If cos(x)=1/4 what is sin(x) and tan(x)
anygoal [31]
You can use the identity
  cos(x)² +sin(x)² = 1
to find sin(x) from cos(x) or vice versa.

  (1/4)² +sin(x)² = 1
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Then the tangent can be computed as the ratio of sine to cosine.
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There are two possible answers.
In the first quadrant:
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  tan(x) = √15

In the fourth quadrant:
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3 0
4 years ago
I just need 30 please
PIT_PIT [208]

In the smaller triangle, let y be the length of the smallest leg. Then the smallest leg in the larger triangle is 14-y.

Within the scope of the smaller triangle, we have y such that

x^2+y^2=13^2\implies y=\sqrt{13^2-x^2}

Then within the larger the triangle, we would have

x^2+(14-y)^2=15^2\iff x^2+\left(14-\sqrt{13^2-x^2}\right)^2=15^2

Now we can solve for x:

x^2+14^2-28\sqrt{13^2-x^2}+(13^2-x^2)=15^2

\implies x=12

8 0
3 years ago
It takes Flora 3 hours to knit a pair of socks and 7 hours to knit a pair of gloves. If she spent 100 hours knitting a total of
gavmur [86]
3 pairs of socks and 13 pairs of gloves
6 0
3 years ago
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