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timama [110]
3 years ago
13

pleaseeeeeeeeeee helppppppppppppppppppp meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee!!!!!!!!!!!!!!!!!!!!!!!!!!!! im literaly us

ing half of my points i have left !!1111

Mathematics
1 answer:
saw5 [17]3 years ago
7 0

Answer: The  amount that they made together is 130,640 The amount that the agency made is 20,240

Step-by-step explanation:

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Which number in the monomial 215x^18y^3z^21 needs to Be changed to make it a perfect cube ?
FinnZ [79.3K]

Hello from MrBillDoesMath!

Answer:  215

Discussion:

Let's start by rewriting the monomial as

215  x^18 y ^3 z^21

Now..

x^ 18 = (x^6)^3

y^3   = (y    )^3

z^21 =  (z^7)^3

So those terms are already cubes!  The only remaining candidate is the number 215, which is not a cube.




Thank you,

MrB


3 0
3 years ago
Find the value of x on both problems please help this is urgent and please show work
puteri [66]

Answer:

Step-by-step explanation:

1) the triangle is right, so we can use the Pythagorean theorem

x^2 + 24^2 = (16+x)^2

x^2 + 576 = x^2 + 256 + 32x

32x = 320

x = 10

2) the two segment are congruent, so

7x - 13 = 9x - 23

2x = 10

x = 5

5 0
3 years ago
What is <br><br> tan(Cos^-1 8/17)
Brrunno [24]

Answer:

<em>Exact Form: </em>

\frac{15}{8}

<em>Decimal Form: </em>

1.875

<em>Mixed Number Form: </em>

\frac7{8}{1}

5 0
3 years ago
The function below models the correlation between the number of hours a plant is kept in sunlight (x) and the height (y), in mm,
RUDIKE [14]
The y int is 4.....and that is the original height of the plant
6 0
3 years ago
Read 2 more answers
The equation of a circle is x^2+y^2-2x +6y-6=0. Find the center and radius of the circle by completing the square.you must inclu
zavuch27 [327]

Answer:

The center of the circle is at;

(1,-3)

The radius of the circle is;

r=4

Explanation:

Given the equation of circle;

x^2+y^2-2x+6y-6=0

we want to re-write it in the form;

(x-h)^2+(y-k)^2=r^2

where;

\begin{gathered} (h,k)\text{ is the center of the circle} \\ r\text{ is the radius} \end{gathered}

Applying Completing the square method;

\begin{gathered} x^2+y^2-2x+6y-6=0 \\ x^2-2x+1+y^2+6y+9=6+1+9 \\ (x-1)^2+(y+3)^2=16 \\ (x-1)^2+(y+3)^2=4^2 \end{gathered}

comparing the derived equation to the general form we have;

\begin{gathered} h=1 \\ k=-3 \\ r=4 \end{gathered}

Therefore;

The center of the circle is at;

(1,-3)

The radius of the circle is;

r=4

6 0
1 year ago
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