All categories

3 years ago

Lucy buys 7kg of nuts to sell.

Mathematics

1 answer:

Nikitich [7]3 years ago

3 0

Answer:

Lucy's percentage profit = 33.33% based on Sales Value

and 50% based on Cost.

Step-by-step explanation:

a) Calculations:

7kg = 7,000g of nuts

Cost of 7,000g = £10

350g = 20 bags (7,000/350)

Sales value = £15 (20 x 75p)

Profit = Sales value minus Cost

Profit = £5 (£15 - £10)

Profit percentage based on sales = Profit/Sales x 100 = 5/15 x 100 = 33.33%

Profit percentage based on cost = Profit/Cost x 100 = 5/10 x 100 = 50%

b) Profit is the excess of sales over cost. There are two ways to express it in percentages. Profit can be expressed as a percentage of the cost (Markup). It can also be expressed as the percentage of the sales value (Margin).

You might be interested in

What ratio is equivalent to 4:5 A. 10/15 B. 4/10 C. 16/20 D. 15/8

laila [671]

The answer is C 16:20 because both numbers 4&5 are multiplied by four

8 0

4 years ago

Read 2 more answers

use slope to determain weather or not quadrilateral ABCD with A(3, 1) B(6, -1) C(1, -3) and D(-2, -1), is a parallelogram

Ksivusya [100]

Answer:

Step-by-step explanation:

8 0

3 years ago

Slope intercept form <br> WILL MARK BRAINLIST

RideAnS [48]

Answer : y= -10/1 x - 30

7 0

3 years ago

Please help me with this equation

vaieri [72.5K]

You need to include a picture or an equation

7 0

3 years ago

A marketing firm is considering making up to three new hires. Given its specific needs, the management feels that there is a 50%

IRISSAK [1]

Answer:

a) 0.9

b) Mean = 1.58

Standard Deviation = 0.89

Step-by-step explanation:

We are given the following in the question:

A marketing firm is considering making up to three new hires.

Let X be the variable describing the number of hiring in the company.

Thus, x can take values 0,1 ,2 and 3.

$P(x\geq 2) = 50\%= 0.5\\P(x = 0) = 10\% = 0.1\\P(x = 3) = 18\% = 0.18$

a) P(firm will make at least one hire)

$P(x\geq 2) = P(x=2) + P(x=3)\\0.5 = P(x=2) + 0.18\\ P(x=2) = 0.32$

Also,

$P(x= 0) +P(x= 1) + P(x= 2) + P(x= 3) = 1\\ 0.1 + P(x= 1) + 0.32 + 0.18 = 1\\ P(x= 1) = 1- (0.1+0.32+0.18) = 0.4$

$\text{P(firm will make at least one hire)}\\= P(x\geq 1)\\=P(x=1) + P(x=2) + P(x=3)\\ = 0.4 + 0.32 + 0.18 = 0.9$

b) expected value and the standard deviation of the number of hires.

$E(X) = \displaystyle\sum x_iP(x_i)\\=0(0.1) + 1(0.4) + 2(0.32)+3(0.18) = 1.58$

$E(x^2) = \displaystyle\sum x_i^2P(x_i)\\=0(0.1) + 1(0.4) + 4(0.32) +9(0.18) = 3.3\\V(x) = E(x^2)-[E(x)]^2 = 3.3-(1.58)^2 = 0.80\\\text{Standard Deviation} = \sqrt{V(x)} = \sqrt{0.8036} = 0.89$

7 0

3 years ago