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2 years ago

For each number, name its opposite. a. -5 b. 28 c. -10.4 d. 0.875 e. 0 f. -8,003

Mathematics

1 answer:

melisa1 [442]2 years ago

5 0

Answer:

5, -28, 10.4, -.875, 0, 8003

Step-by-step explanation:

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The speed of Natalie in miles per hour is 1.2 mph.

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Chicken is normally $2.15/lb. but if you purchase 26 pounds for $41.34, how much do you save per pound?

swat32

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Step-by-step explanation: If you take $41.34 divided by 26 you get $1.59. Then, take $2.15-$1.59.

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Step-by-step explanation:

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3 years ago

NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions

Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector $\vec{v}$ in some vector space $\mathbb R^n$ we have

$\vec{v} = \langle a,b\rangle$

This is the component form. I don't like that way. It is probably used in high school, but

$\vec{v} = \begin{pmatrix} a\\ b\\ \end{pmatrix}$

is preferable because the inner product on $\mathbb R^n$ is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as $\vec{v} = 2i+2j$

For this question, I think you meant

vectors

$\vec{u_1} = (-8, 12)$

$\vec{u_2} = (13, 15)$

Once

$\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}$

Considering that the dot product is

$\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76$

and the norm of $\vec{u_1}$ is $||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}$

and the norm of $\vec{u_2}$ is $||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}$

Thus,

$\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}$

$\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)$

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2 years ago

Gage's math teacher entered the seventh-grade student in a math competition. There was an enrollment fee of $30 and also $11 cha

Amanda [17]

Answer:

110 test

Step-by-step explanation:

Let

x ----> the number of packet of 10 test

y ----> the total cost

we know that

The number of packet of 10 test purchase multiplied by $11 plus the enrollment fee of $30 must be equal to $151

The linear equation that represent this scenario is

$y=11x+30$

we have

$y=\$151$

substitute

$151=11x+30$

Solve for x

subtract 30 both sides

$11x=151-30$

$11x=121$

Divide by 11 both sides

$x=11$

The number of packets purchase was 11

To find out the number of test, multiply the number of packets by 10

$11(10)=110\ test$

4 0

3 years ago