All categories

3 years ago

14+12n=11n-37 what is N

Mathematics

2 answers:

zaharov [31]3 years ago

8 0

Combine like terms and then simplify

Fofino [41]3 years ago

7 0

14 + 12n = 11n - 37

+37 -12n = -12n +37

51 = -1n

/-1 /-1

-51 = n

~~~~~~~~~~~~~~~~~~~~~~~

PLEASE RATE AS THE BRAINLIEST ANSWER! THANK YOU! :)

You might be interested in

Learning Theory In a typing class,the averege number N of words per minutes typed after t weeks of lessons can be modeled by N =

Jet001 [13]

Answer:

a) $N(t=10) = \frac{95}{1+8.5 e^{-0.12(10)}}= \frac{95}{1+ 8.5 e^{-1.2}} = 26.684$

b) $N(t=20) = \frac{95}{1+8.5 e^{-0.12(20)}}= \frac{95}{1+ 8.5 e^{-2.4}} = 53.639$

c) $70 =\frac{95}{1+8.5 e^{-0.12t}}$

$1+ 8.5 e^{-0.12t} = \frac{95}{70}= \frac{19}{14}$

$8.5 e^{-0.12t} = \frac{19}{14}-1= \frac{5}{14}$

$e^{-0.12t} = \frac{\frac{5}{14}}{8.5}= \frac{5}{119}$

$ln e^{-0.12t} = ln (\frac{5}{119})$

$-0.12 t = ln(\frac{5}{119})$

$t = \frac{ln(\frac{5}{119})}{-0.12} = 26.414 weeks$

d) If we find the limit when t tend to infinity for the function we have this:

$lim_{t \to \infty} \frac{95}{1+8.5 e^{-0.12t}} = 95$

So then the number of words per minute have a limit and is 95 as t increases without bound.

Step-by-step explanation:

For this case we have the following expression for the average number of words per minutes typed adter t weeks:

$N(t) = \frac{95}{1+8.5 e^{-0.12t}}$

Part a

For this case we just need to replace the value of t=10 in order to see what we got:

$N(t=10) = \frac{95}{1+8.5 e^{-0.12(10)}}= \frac{95}{1+ 8.5 e^{-1.2}} = 26.684$

So the number of words per minute typed after 10 weeks are approximately 27.

Part b

For this case we just need to replace the value of t=20 in order to see what we got:

$N(t=20) = \frac{95}{1+8.5 e^{-0.12(20)}}= \frac{95}{1+ 8.5 e^{-2.4}} = 53.639$

So the number of words per minute typed after 20 weeks are approximately 54.

Part c

For this case we want to solve the following equation:

$70 =\frac{95}{1+8.5 e^{-0.12t}}$

And we can rewrite this expression like this:

$1+ 8.5 e^{-0.12t} = \frac{95}{70}= \frac{19}{14}$

$8.5 e^{-0.12t} = \frac{19}{14}-1= \frac{5}{14}$

Now we can divide both sides by 8.5 and we got:

$e^{-0.12t} = \frac{\frac{5}{14}}{8.5}= \frac{5}{119}$

Now we can apply natural log on both sides and we got:

$ln e^{-0.12t} = ln (\frac{5}{119})$

$-0.12 t = ln(\frac{5}{119})$

And then if we solve for t we got:

$t = \frac{ln(\frac{5}{119})}{-0.12} = 26.414 weeks$

And we can see this on the plot 1 attached.

Part d

If we find the limit when t tend to infinity for the function we have this:

$lim_{t \to \infty} \frac{95}{1+8.5 e^{-0.12t}} = 95$

So then the number of words per minute have a limit and is 95 as t increases without bound.

8 0

3 years ago

I need help with Exponential Equations, where can i go to get answers

True [87]

There are some online calculators

7 0

3 years ago

What times what equals 36 and add up to 11

kotegsom [21]

9 and 4. 9*4 = 36, 9 + 4 =1 1.

8 0

4 years ago

Polygon A and Polygon B are similar with a ratio of similarity of 5/4. If the perimeter of Polygon A is 20 units, what is the pe

klemol [59]

Answer:

16 units

Step-by-step explanation:

A/B = 5/4 = 20/p

5/4 = 20/p

5p = 4 × 20

p = 4 × 4

p = 16

Answer: 16 units

6 0

2 years ago

bixtya [17]

Using an exponential function, it is found that f(5.5) = 19.8.

<h3>What is an exponential function?</h3>

An exponential function is a function in which the growth rate is a percentage, modeled by:

$y = ab^x$

In which:

a is the initial value.

b is the rate of change.

f(3.5) = 25 means that:

$ab^{3.5} = 25$

$a = \frac{25}{b^{3.5}}$

f(8.5) = 14 means that:

$ab^{8.5} = 14$

Hence:

$\frac{25}{b^{3.5}} \times b^{8.5} = 14$

$25b^5 = 14$

$b = \sqrt[5]{\frac{14}{25}}$

$b = 0.89$

$a = \frac{25}{0.89^{3.5}} = 37.59$

Hence, the function is given by:

$y = 37.59(0.89)^x$

Then, when x = 5.5:

$f(5.5) = 37.59(0.89)^{5.5} = 19.8$

More can be learned about exponential functions at brainly.com/question/25537936

7 0

2 years ago