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algol [13]
2 years ago
5

Find the product of the given polynomials. (5x + 8 – 6r) (4 + 2r – 7)​

Mathematics
1 answer:
Inessa05 [86]2 years ago
6 0

Answer:

-12r² + 10xr - 15x + 34r - 24

Step-by-step explanation:

1. Organize it, variables first - as well as adding constants such as 4 and -7

(5x - 6r + 8) (2r - 3)

2. Start by multiplying the 5x by (2r - 3), then -6r, followed by 8

(10xr - 15x) + (-12r^2 + 18r) + (16r - 24)

3. Simplify

10xr - 15x - 12r² + 18r + 16r - 24

4. Order by greatest to smallest factorial

-12r² + 10xr - 15x + 18r + 16r - 24

5. Combine like variables

-12r² + 10xr - 15x + 34r - 24

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Andrei [34K]
Hello,

\dfrac{(2a^{3})^{-3}}{3b*(-2)}=-\dfrac{1}{(2a^3)^3*6b}=-\dfrac{1}{48a^9b}



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2 years ago
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Novosadov [1.4K]

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1 year ago
What is the range of y = (x - 5)^2 – 1?
Setler79 [48]

1.  The graph is a parabola.

2. The parabola opens up, because there's no negative number in front of (x-5)^2.

3. The vertext is (5,-1), because of the vertex form.

This means that that -1 will be the least y-value used on the graph and the garph will open up from there.

The range is (-1, infinity) or { y | y > -1 }.

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2 years ago
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Answer:

I think it should be 24x^{2}

Step-by-step explanation:

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