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IgorLugansk [536]
2 years ago
11

In a game against the Creek Side

Mathematics
1 answer:
frosja888 [35]2 years ago
4 0
Classify the graph as a linear function, nonlinear function, or relation (non- function) 10 O A. Linear function B.
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Please help me i really need help please help me
Lapatulllka [165]

Answer:

The total surface is 48 ft

Step-by-step explanation:

5 0
2 years ago
Could these side lengths make a right triangle, 12m, 35m and 37m
natta225 [31]

Answer:

Yes

Step-by-step explanation:

Using Pythagorean theorem WHICH ONLY WORKS FOR RIGHT TRIANGLES,

a^2+b^2=c^2 where a and b are the two shortest legs.

12^2+35^2=c^2

144+1225=c^2

c^2=1369

c=\sqrt{1369}

c=37

3 0
2 years ago
Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x.
Leni [432]

Answer:

a)

g(2.9) \approx -6.6

g(3.1) \approx -3.4

b)

The values are too small since g'' is positive for both values of x in. I'm speaking of the x values, 2.9 and 3.1.

Step-by-step explanation:

a)

The point-slope of a line is:

y-y_1=m(x-x_1)

where m is the slope and (x_1,y_1) is a point on that line.

We want to find the equation of the tangent line of the curve g at the point (3,-5) on g.

So we know (x_1,y_1)=(3,-5).

To find m, we must calculate the derivative of g at x=3:

m=g'(3)=(3)^2+7=9+7=16.

So the equation of the tangent line to curve g at (3,-5) is:

y-(-5)=16(x-3).

I'm going to solve this for y.

y-(-5)=16(x-3)

y+5=16(x-3)

Subtract 5 on both sides:

y=16(x-3)-5

What this means is for values x near x=3 is that:

g(x) \approx 16(x-3)-5.

Let's evaluate this approximation function for g(2.9).

g(2.9) \approx 16(2.9-3)-5

g(2.9) \approx 16(-.1)-5

g(2.9) \approx -1.6-5

g(2.9) \approx -6.6

Let's evaluate this approximation function for g(3.1).

g(3.1) \approx 16(3.1-3)-5

g(3.1) \approx 16(.1)-5

g(3.1) \approx 1.6-5

g(3.1) \approx -3.4

b) To determine if these are over approximations or under approximations I will require the second derivative.

If g'' is positive, then it leads to underestimation (since the curve is concave up at that number).

If g'' is negative, then it leads to overestimation (since the curve is concave down at that number).

g'(x)=x^2+7

g''(x)=2x+0

g''(x)=2x

2x is positive for x>0.

2x is negative for x.

That is, g''(2.9)>0 \text{ and } g''(3.1)>0.

So 2x is positive for both values of x which means that the values we found in part (a) are underestimations.

6 0
3 years ago
Write an equation of the line that has a slope of 3 and contains the point (2,5) in point-slope for
enot [183]
The equation would be y=3x-1

Point Slope Formula: 

y - y1 = m(x - x1)

y - 5 = 3(x-2)
y - 5 = 3x - 6
  + 5        + 5
--------------------
y = 3x - 1


8 0
3 years ago
Read 2 more answers
Ann took a taxi home from the airport. The taxi fare was \$2.10$2.10 per mile, and she gave the driver a tip of \$5$5. Ann paid
Stolb23 [73]

Answer:

If your wondering how many miles the taxi drove the answer is 21 miles

Step-by-step explanation:


5 0
2 years ago
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