The domain: D={-3;-2;-1; 1}
f(x) = -x + 4
subtitute
f(-3) = -(-3) + 4 = 3 + 4 = 7
f(-2) = -(-2) + 4 = 2 + 4 = 6
f(-1) = -(-1) + 4 = 1 + 4 = 5
f(1) = -1 + 4 = 3
Answer: The range: {3; 5; 6; 7}
Answer:
12
Step-by-step explanation:
Since this is simple interest the equation will be P*T*R=I T=time which is 1 year. P=money invested or borrowed (aka princable) which is 400$. R=Annual rate is 3% per year and I= Interest after the number of years (aka answer) Hope this helps :)
Answer:
i). x³ + 9x² + yz - 15
ii). -21m³np - 8p⁵q + mnp + 4mn + 100
Step-by-step explanation:
Question (38)
i). Two expressions are -5x² - 4yz + 15 and x³+ 4x²- 3yz
By subtracting expression (1) from expression (2) we can the expression by addition which we can get expression (1).
(x³+ 4x²- 3yz) - (-5x² - 4yz + 15) = x³ + 4x² - 3yz + 5x² + 4yz - 15
= x³ + 9x² + yz - 15
ii). -15m³np + 2p⁵q - 6m³pn + mnp + 4mn - 10qp⁵+ 100
= (-15m³np - 6m³np) + (2p⁵q - 10qp⁵) + mnp + 4mn + 100
= -21m³np - 8p⁵q + mnp + 4mn + 100
The answer is B!
Hoped I Helped!
If I’m wrong don’t blame me
Answer:
tan(Sin^-1 x/2)= 
Step-by-step explanation:
Let sin^-1 x/2= θ
then sinθ= x/2
on the basis of unit circle, we have a triangle with hypotenuse of length 1, one side of length x/2 and opposite angle of θ.
tan(Sin^-1 x/2) = tanθ
tanθ= sinθ/cosθ
as per trigonometric identities cosθ= √(1-sin^2θ)
tanθ= sinθ/ √(1-sin^2θ)
substituting the value sinθ=x/2 in the above equation
tanθ=
now substituting the value sin^-1 x/2= θ in above equation
tan(sin^-1 x/2) =
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