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Dovator [93]
3 years ago
11

Zorah, a musician, pays $120 to have her instrument tuned and $10 per hour for a booth at a fair. She estimates that she earns $

25 per hour in tips. The equation can be used to represent the break-even point. 120 + 10x = 25x How many hours, x, will Zorah have to play in order to break even? 4 5 8 12
Mathematics
2 answers:
vitfil [10]3 years ago
8 0

Answer:

8 hours

Step-by-step explanation:

Solve for x in the given equation:

120+10x = 25x

120 = 15x

x = 8

boyakko [2]3 years ago
6 0

Answer:

8 hours bruh, i just took the test

Step-by-step explanation:

Edg 2020

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(0.08x)(x+-200)
(0.08x)(x)(0.08x)(-200)
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3 0
3 years ago
How to solve this question?<br><br><br> Show steps pls :)
Svetlanka [38]

Answer:

Bro if u don't know the ques then ask ur mom or dad kid

4 0
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Solve r = 4/3(p-q) for p
ddd [48]

Answer:

q+3/4r=p

Step-by-step explanation:

r=4/3(p-q)

Distribute the 4/3

r=4/3p-4/3q

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6 0
3 years ago
Use the following matrices, A, B, C and D to perform each operation.
Vinvika [58]

Step-by-step explanation:

A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]

B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]

C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]

D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]

1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]

2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]

3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]

4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]

5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}

6 0
3 years ago
I will mark u brainalist
melisa1 [442]

Answer:

1) Positive

2) Undefined

3) Negative

4) Zero

<h2><u>Hope This Helped!</u></h2>

3 0
2 years ago
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