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3 years ago

PLEASE HELP

Mathematics

2 answers:

Gnesinka [82]3 years ago

3 0

ANSWER

Step-by-step explanation:

d=√((x_2-x_1)²+(y_2-y_1)²)

Scilla [17]3 years ago

3 0

Answer:

hey can you explain cause IM reading my self and id be happy to help if you oh you have a picture oh the answer is...

Step-by-step explanation:

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Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.

NISA [10]

Answer:

$\frac{\sqrt{\pi}}{4}$

Step-by-step explanation:

You are going to integrate the following function:

$g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}$ (1)

furthermore, you know that:

$\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}$

lets call to this integral, the integral Io.

for a general form of I you have In:

$I_n=\int_0^{\infty}x^ne^{-ax^2}dx$

furthermore you use the fact that:

$I_n=-\frac{\partial I_{n-2}}{\partial a}$

by using this last expression in an iterative way you obtain the following:

$\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}}$ (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

$\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}$

5 0

3 years ago

Read 2 more answers

At one store, Julia saved $10 with a coupon for 40% off her total purchase. At another store, the $29 she spent on books is

barxatty [35]

Let "a" and "b" represent the values of the first and second purchases, respectively.
0.40*(original price of "a") = $10
(original price of "a") = $10/0.40 = $25.00 . . . . divide by 0.40 and evaluate
a = (original price of "a") - $10 . . . . . . Julia paid the price after the discount
a = $25.00 -10.00 = $15.00

At the other store,
$29 = 0.58b
$29/0.58 = b = $50 . . . . . . . divide by the coefficient of b and evaluate

Then Julia's total spending is
a + b = $15.00 +50.00 = $65.00

Julia spent $65 in all at the two stores.

6 0

3 years ago

The square root of 1/144 simplified

PSYCHO15rus [73]

1/12 is the square root of 1/144

8 0

3 years ago

Find a common factor for 3y^3+2y^2 and 6y^4+4y^3

Anit [1.1K]

Answer:

$3y + 2$

Step-by-step explanation:

We want to find a common factor for

$3 {y}^{3} + 2 {y}^{2}$

and

$6 {y}^{4} + 4 {y}^{3}$

We factor each of them to get;

$3 {y}^{3} + 2 {y}^{2} = {y}^{2} (3y + 2)$

and

$6 {y}^{4} + 4 {y}^{3} = 2 {y}^{3} (3y + 2)$

We can observe now that;

The factor common to both expression is

$3y + 2$

7 0

3 years ago

An advertising company charges $60 per half-page advertisement and $100 per full-page advertisement. Michael has a budget of $13

krek1111 [17]

Answer:

The number of half-page advertisements is 4.

The number of Full-page advertisements is 11.

Step-by-step explanation:

According to the Question,

Given, An advertising company charges $60 per half-page advertisement and $100 per full-page advertisement. Michael has a budget of $1340 to purchase 15 advertisements.

Let, 'x' be the number of half-page advertisements and 'y' be the number of full-page advertisements.

Thus, 60x + 100y is the money charged, and given that he has a budget of $ 1340.

60x + 100y = 1340

And, the number of advertisements is 15. So, the other equation is

x + y = 15

Now, We have Two Equations,

60x + 100y = 1340 and x + y = 15

the solution of the system is Put x=(15-y) in Equation 60x + 100y = 1340

60 (15-y) + 100y = 1340

900 - 60y + 100y = 1340

40y = 1340 - 900

40y = 440

y = 440/40

y = 11 So, For x = 15 - y ⇒ 15-11 ⇒ x=4 .

Thus, the number of half-page advertisements is 4 and The number of Full-page advertisements is 11 .

6 0

3 years ago