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3 years ago

PLEASE HELP

Mathematics

2 answers:

Gnesinka [82]3 years ago

3 0

ANSWER

Step-by-step explanation:

d=√((x_2-x_1)²+(y_2-y_1)²)

Scilla [17]3 years ago

3 0

Answer:

hey can you explain cause IM reading my self and id be happy to help if you oh you have a picture oh the answer is...

Step-by-step explanation:

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Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$

NOTE: sin²θ + cos²θ = 1

$\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}$

$\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}$

$\dfrac{2sec^2\theta}{tan^2\theta-1}$

Left side = Right side <em>so proof is complete</em>

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3 years ago

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You scored 31 out of 40 points on a test. What percent did you get?

elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

Divide 31 by 40. Since you get .775, you make it a percent and it's 77.5% correct.

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3 years ago

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vova2212 [387]

Answer:

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Step-by-step explanation:

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3 years ago

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Sholpan [36]

Answer:

They went up 16 levels.

Step-by-step explanation:

You can find that by finding the distance from -2 to 14.
To find the distance from two numbers, $a$ and $b$ , we can substitute both in the formula $d = |b - a|$ , where d is the distance between them.

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1 year ago

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C. If a < 0 and f(a) > 0, then the point (a, f(a))

professor190 [17]

The answer is: b - lies in quadrant II when graphed.

Explanation:

Any number less than zero is a negative number.

Example: -1

Any number greater than zero is a positive number.

Example: 1

(a, f(a))

(-1,1)

When these example points are graphed, they are placed in the second quadrant.

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2 years ago