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marissa [1.9K]
3 years ago
11

PLEASE HELP

Mathematics
2 answers:
Gnesinka [82]3 years ago
3 0

ANSWER

D

Step-by-step explanation:

d=√((x_2-x_1)²+(y_2-y_1)²)

Scilla [17]3 years ago
3 0

Answer:

hey can you explain cause IM reading  my self and id  be happy to help if you  oh you have a picture oh the answer is...

Step-by-step explanation:

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Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
You scored 31 out of 40 points on a test. What percent did you get?
elena-14-01-66 [18.8K]

Answer:


Step-by-step explanation:

Divide 31 by 40. Since you get .775, you make it a percent and it's 77.5% correct.

5 0
3 years ago
I need help people get brailestttt
vova2212 [387]

Answer:

Whats the question?

Step-by-step explanation:

7 0
3 years ago
PLS HELP ME 50 POINTS!!!!! I NEED AN ANSWER ASAP!!!!!!
Sholpan [36]

Answer:

They went up 16 levels.

Step-by-step explanation:

You can find that by finding the distance from -2 to 14.
To find the distance from two numbers, a and b, we can substitute both in the formula d = |b - a|, where d is the distance between them.

d = |14 - (-2)| \to |14 + 2|\to|16|\to16

4 0
1 year ago
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C. If a &lt; 0 and f(a) &gt; 0, then the point (a, f(a))
professor190 [17]
The answer is: b - lies in quadrant II when graphed.

Explanation:

Any number less than zero is a negative number.

Example: -1

Any number greater than zero is a positive number.

Example: 1

(a, f(a))

(-1,1)

When these example points are graphed, they are placed in the second quadrant.
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