<span>let:
m1 = 2xy a
m2 = 2xy b
m3 = 2x2y c
since 2 and 3 have a common factor let b=2n
m1 = 2xy a
m2 = 2xy 2 n
m3 = 2x2y c
or simply
m1 = 2xy a
m2 = 2xy 2n
m3 = 2xy 2c
given that anc have no common factors</span>
Answer:
no equation given ,pls mention it in the comments
Answer:
- ∠R = 56°
- ∠Q = 90°
- ∠S = 34°
Step-by-step explanation:
The given triangle is a right angled triangle.
So, the angles in the triangle are :
- 90°
- (2x + 38)°
- (5x - 11)°
Solving according to <u>angle sum property</u>,
Sum of all angles in a triangle is 180°
90° + (2x + 38)° + (5x - 11)° = 180°
117° + 7x = 180°
7x = 180° - 117°
7x = 63°
x = 9
Angles =
2(9) + 38
56°
5(9) - 11
34°
- ∠R = 56°
- ∠Q = 90°
- ∠S = 34°
The angles are 56°, 90° and 34°.
Answer:
m ≠1 ( all m in R except 1 )
Step-by-step explanation:
hello :
mx − y + 3 = 0.....(*)
(2m − 1)x − y + 4 = 0 ....(**)
multiply (*) by : -1 you have : -mx+y-3=0 ....(***)
(2m − 1)x − y + 4 = 0 ....(**)
add(***) and(**) : -mx+ (2m − 1)x+1 =0
(2m-m-1)x+1=0
(m-1)x = -1
this system have no solution if : m-1≠0 means : m ≠1
Answer:
And we can find this probability with this difference and using the normal standard table:
Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women
Step-by-step explanation:
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where
and
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability with this difference and using the normal standard table:
Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women