Since you're not multiplying, you can remove the parentheses.
3b+6+2
which gives you . ....
3b+8
(4x - 1)2 = 11
(4x - 1) = 22
4x - 1 = 22
4x = 23
x = 5.75
False. When a quadrilateral has two sets of parallel sides ,like I drew below, all four corners form right angles.
Answer: x>_3.2 OR x<_ -0.75
Step-by-step explanation: first break down your compound inequality. 5x-4>_12
You first cancel out your constants by adding 4 to both sides. Now you’re left with 5x>_16 then to cancel five you have to divide on both sides by five which equals to 3.2. Then, x>_ 3.2.
Next you do your second part, 12x+5<_-4
So first cancel out the constant of 5 by subtracting 5 on both sides, making the equation 12x<_-9. Now, you divide by 12 on both sides, making it -9/12. Which effectively is -0.75. Therefor, the answer being x<_ -0.75. Add the two together x>_3.2 OR x<_0.75