Answer:
a) The set of natural numbers greater than or equal to 3 and less than or equal to 6.
b) {3,4,5,6}
Step-by-step explanation:
a) The Roster form is given as {6,8,10,12,...}
The descriptive form is a phrase that describes the given set.
The descriptive form is: <em>The set of even natural numbers greater than or equal to 6.</em>
b) The descriptive form is : The set of natural numbers greater than or equal to 3 and less than or equal to 6.
The Roster form is obtained by listing the numbers between 3 and 6 inclusive in curly brackets.
The Roster form is : {3,4,5,6}
The domain of the function is [-4, 4) and the range of the function is [-5, 2)
<h3>How to determine the domain and the range of the function?</h3>
<u>The domain</u>
As a general rule, it should be noted that the domain of a function is the set of input values or independent values the function can take.
This means that the domain is the set of x values
From the graph, we have the following intervals on the x-axis
x = -4 (closed circle)
x =4 (open circle)
This means that the domain of the function is [-4, 4)
<u>The range</u>
As a general rule, it should be noted that the range of a function is the set of output values or dependent values the function can produce.
This means that the range is the set of y values
From the graph, we have the following intervals on the y-axis
y = -5 (closed circle)
y = 2 (open circle)
This means that the range of the function is [-5, 2)
Read more about domain and range at:
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B 3/7 because 15 divided by 5 = 3 and 35 divided by 5 = 7
3,500 (.024) = 84
84 (5) = $420 in simple interest
Answer:
x=90° and y=35°
Step-by-step explanation:
to get x and y first you must find the middle angles based on the information you have so:
35+90+n=180° solve for n to get what the middle angles are (since they are vertical angles they are equal) so the middle angles are both 55 degrees
and then 180-x=that angle that is also on the line with x so we'll call it k
so k+55+y=180°
we can see that y equals 35* because I noticed that those are parallel lines on the outside of the triangle so 35* and y angles are congruent and y =35°
now 35+55+k=180°
solve for the angle next to x which we called k and it is 90°
so x=90° and y=35°
after all this math I realized that if they are parallel lines then we can just use that to figure it out so use the properties to find out that x=90° and y=35°
