A=(3.14)r^2
A=(3.14)3^2
A=(3.14)9
A=28.26ft^2
Hope it helps and is correct :)
Answer:
The Magnitude of charge = q = 15.47 micro coulomb
Step-by-step explanation:
The attractive force between two points q and - 2 q = F = 2.2 Newton
The separation between two charges = 1.4 meters
Now from Coulomb's law = F = 
where k= 
So , 2.2 = ( 
So , q ² = (
)
For charge magnitude
I.e q ² = 
so, q = 
q = 15.47 \times 10^{-6} c
Or, q = 15.47 micro coulomb
Hence the Magnitude of charge = q = 15.47 micro coulomb Answer
Answer: d) 255 ≤ f(x) ≤ 340
Step-by-step explanation:
The function
f(x)= 8.5x
represents the amount of money that Steve earns given the number of hours, x, he works.
The dependent variable is the total amount that he earns, f(x) while the independent variable is the number if hours, x that he works. The range is the possible values of the dependent variable that satisfies the equation.
Steve works between 30 and 40 hours per week. This means that
the lowest amount that he earns is 8.5×30 = $255
The highest amount that he earns is 8.5× 40 = 340. Therefore, the range is
255 ≤ f(x) ≤ 340
Answer: x-value
Step-by-step explanation:
the x-value is the input, domain and 1st element.
Answer:
21 adults and 139 children
Step-by-step explanation:
x=adult (8$)
y=child (5$)
8x + 5y =863
x+y=160
-x -x (subtract x on both sides)
y= -x + 160
plug that in for y on the other equation
8x + 5(-x + 160) =863
distribute 5 to both
8x + -5x + 800 = 863
combine both x values
3x + 800 = 863
-800 -800 (subtract on both sides)
3x = 63
divide by 3 on both sides
x = 21 adults
now plug x in one of the equations
21 + y = 160
-21 -21
y=139 children
