Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Slope formular = (y2-y1)/(x2 - x1)
so
slope = (-6 +5)/(-4-3)
slope = -1/-7
slope = 1/7
answer
Laila is correct
Answer:
C). 0 degrees
Step-by-step explanation:
The given equation is:
-4 + 6 sinx = -4 + 4 sinx
adding 4 on both sides:
4 - 4 + 6 sinx = 4 - 4 + 4 sinx
6sinx = 4sinx
dividing by 2 on both sides, we get:
6sinx/2 = 4sinx/2
3 sinx = 2 sinx
subtracting 2 sinx from both sides we get:
sin x = 0
x = sin⁻¹ (0)
x = 0 degrees
Answer:
uh....…....…....….…..……..…
Step-by-step explanation:
uh....…....…....…..……..…..…
The rate of change for one hour is 4°.
When you look at the problem it says the temperature dropped 24° in 6 hours . So if you divided 24 by 6 you get 4 which is the rate at which the temperature dropped per hour.