Answer:
A
Step-by-step explanation:
1). Am I seated comfortably, with plenty of light on my paper ?
2). Is my pencil sharp ?
In y = mx + b form, which is what ur equation is in, the y int can be found in the b position
y = mx + b
y = x + 6
as u can see, the number in the b position, ur y int, is 6 <==
I believe y=x+2 and y=-x+3 are perpendicular lines.
You would use the point-slope equation of y-y₁=mx(x-x₁)
So the rate of change is the slope and equals m, so m=-4
and has a solution at (-5,2) which would be the (x₁, y₁) and then it is just plugging in the numbers
y - (2) = (-4)(x - (-5))
y - 2 = -4 (x+5)
y - 2 = -4x - 20
y = -4x - 18