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viktelen [127]
3 years ago
7

A part of Jennifer’s work is to solve the equation 2(6x^2-3)=11x^2-x is shown below

Mathematics
1 answer:
kotykmax [81]3 years ago
7 0

Answer:

Step-by-step explanation:

2(6x² - 3) = 11x² - x

2*6x² - 2*3 = 11x² - x

12x² - 6 = 11x² -x

Subtract 11x² from both sides

12x² - 11x² - 6 = -x

x² - 6 = -x

x² + x - 6= 0

Sum =1

Product = -6

Factors =  3 , (-2)              { 3*(-2)  = -6   & 3 +(-2) = 1}

x² + 3x - 2x - 6 = 0

x(x + 3) - 2(x + 3)= 0

(x +3)(x - 2) = 0

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Variable y varies directly with x2, and y = 96 when x = 4.
lakkis [162]
Direct variation is y = kx, where k is the constant of variation.
 But now it says y varies directly with x2 (or 2x), so now the x in the equation is 2x.

The equation is y = k(2x)
 Now you find k.
y = 96 when x = 4.
(96) = k(2*4)
96 = k(8)
k = 12
 
The equation is now y = 12(2x)
To find the value of y when x=2, plug 2 into the equation you made. y = 12(2*2) y = 48
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Now it's with a "quadratic variation," which is the same thing except x is squared.
The equation is y = kx^2
 
But y varies directly with x2 (same thing as 2x), so now it's y = k(2x)^2.
 
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y = 180 when x = 6
(180) = k(2*6)^2
180 = k(12)^2
180 = k(144)
k = 1.25
k, 1.25, is the constant of variation.
4 0
3 years ago
Same value as 40% of 84
nordsb [41]

Answer:

33.6

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Step-by-step explanation:

4 0
3 years ago
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krok68 [10]
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3 years ago
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jekas [21]

Answer:

y = -5x - 21

Step-by-step explanation:

Given in the question,

equation of a parallel line

y = -5x + 6

point through which it passes

(-4,-1)

Step1

Find the gradient of the equation given, as it is parallel so it will have same gradient

equation of straight line

y = mx + c

where m is gradient

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y = -5x + 6

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Step2

Find y-intercept

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Step3

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y = -5x - 21

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