What is a rule or statement that is always true

A 748-N man stands in the middle of a frozen pond of radius 4.0 m. He is unable to get to the other side because of a lack of fr

Ber [7]

Answer:

The man will take 64 seconds to reach to the south shore of the frozen pond.

Step-by-step explanation:

Given:

Weight of the man = 748 N Mass of the man, $(m)= \frac{W}{g}$ = $\frac{748}{9.8}$ = $76.32$ kg

Radius of the pond $(r)$ = 4 m

Mass of the textbook = 1.2 kg

Velocity at which the textbook is thrown = 4 ms^1

We have to find the velocity of the man after the throw.

Let the velocity is $V_m$ .

Now using law of conservation of momentum we can find the $V_m$ value.

$m_(_b_)V_b_(_i_) +m_(_m_)V_m_(_i_) =m_(_b_)V_b_(_f_)+m_(_m_) V_m_(_f_)$

Considering $V_m_(_f_)=V_m$

And initial velocity of both the man and book i.e $V_b_(_i_)=0,\ V_m_(i_)=0$

So,

⇒ $0 =m_(_b_)V_b_(_f_)+m_(_m_) V_m$

⇒ Plugging the values.

⇒ $V_m=-\frac{m_(_b_)V_b_(_f_)}{m_(_m_)}$

⇒ $V_m=-\frac{1.2\times 4}{76.32}$

⇒ $V_m=-0.062$ ms^-1

Here the negative velocity is meant for opposite direction of the throw.

Numerically we will write, $V_m = 0.062$

With this velocity the man will move towards south.

We have to calculate the time taken by the man to move to its south shore.

And we know $velocity(v)\times time(t) = distance(d)$

Let the time taken be $t$ and $v\times t = d$ and $d=r$ then, $V_m\times t=r$

Then

⇒ $t=\frac{radius\ (r)}{V_m}$

⇒ Plugging the values.

⇒ $t=\frac{4}{0.062}$

⇒ $t =64$ sec

The man will take 64 seconds to reach to the south shore of the frozen pond (circular).

5 0

2 years ago

Can someone actually help me please?

Tamiku [17]

D and B is the anwser

5 0

2 years ago

Evaluate q^2-5q+4, when q equals -2

Anastasy [175]

Answer:

18

Step-by-step explanation:

q^2 - 5q +4

Let q = -2

(-2)^2 - 5(-2) +4

4 + 10 +4

18

8 0

3 years ago

Donelle wants to use his dividends to purchase more stock. He owns 895 shares in a fast food company priced at $17.25. How many

iVinArrow [24]

Answer:

34

Step-by-step explanation:

7 0

3 years ago

Which geometric series diverges? Three-fifths three-tenths three-twentieths StartFraction 3 Over 40 EndFraction ellipsis Negativ

Sholpan [36]

The geometric series which diverges is shown in the option number c as the absolute value of the common ratio of this series 4.

$\sum_{n=1 }^{\infty} \dfrac{2}{3}(-4)^{n-1}$

<h3>What is geometric series diverges? </h3>

Geometric sequence is the sequence in which the next term is obtained by multiplying the previous term with the same number for the whole series.

It can be given as,

$a+ar+ ar^2+ ar^3+...$

Here,

is the (<em>a</em>) first term of the sequence, and (<em>r</em>) is the common ratio.

To be a series as geometric series diverges, it should follow,

$|r| > 1$

First option given as,

3/5+3/10+3/20+3/40+ ...

Here, the common ratio is,

$r=\dfrac{\dfrac{3}{10}}{\dfrac{3}{5}}\\r=\dfrac{1}{2}$

The common ratio is less than one. Thus option a is not correct.

First option given as,

-10+4-8/4+18/25- ...

Here, the common ratio is,

$r=\dfrac{4}{-10}\\r=\dfrac{-2}{5}$

For the option number two the common ratio is (-2/5) which is less than 1. This option is also not correct.

In the option number c, the value of common ratio is -4. The absolute value of common ratio is,

$|r|=|-4|\\|r|=4$

The absolute value of this common ratio is more than one. Thus, this is the correct option.

The geometric series which diverges is shown in the option number c as the absolute value of the common ratio of this series 4.

$\sum_{n=1 }^{\infty} \dfrac{2}{3}(-4)^{n-1}$

Learn more about the geometric sequence here;

brainly.com/question/1509142

7 0

2 years ago