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andrew-mc [135]
3 years ago
5

What is the final concentration of a solution prepared by diluting 35.0 mL of 12.0 M HCl to a final volume of 1.20 L

Chemistry
1 answer:
sineoko [7]3 years ago
8 0

Answer: The final concentration of a solution is 0.350 M

Explanation:

According to the dilution law,

C_1V_1=C_2V_2

where,

C_1 = concentration of concentrated acid solution = 12.0 M

V_1 = volume of concentrated acid solution = 35.0 ml

C_2 = concentration of diluted acid solution= ?

V_2 = volume of another acid solution= 1.20 L = 1200 ml

( 1L=1000ml)

Putting in the values:

12.0\times 35.0=C_2\times 1200

C_2=0.350M

The final concentration of a solution prepared by diluting 35.0 mL of 12.0 M HCl to a final volume of 1.20 L is 0.350 M

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How much carbon dioxide is released when it is fully combusted with 4Kg of ethanol with more than enough oxygen? How do you work
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5 0
3 years ago
You titration 5.0 mL of HCl with 0.010 M NaOH. You find the end point of your titration occurs when 12.0 mL of NaOH has been add
Nookie1986 [14]

your answer is 0.00833M the volume was converted into liters

NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)

Using the molarity equation, we can find the number of moles of HCl that reacted:

molarity=mol soluteL soln

mol solute=(molarity)(L soln)

mol HCl=(0.105molL)(0.0250L)=0.00263 mol HCl

(volume converted to liters)

Now, using the coefficients of the chemical reaction, we can determine the number of moles of NaOH that reacted:

0.00263mol HCl(1lmol NaOH1mol HCl)=0.00263 mol NaOH

Lastly, we'll use the molarity equation (using given volume of NaOH soln) again to determine the molarity of the sodium hydroxide solution:

molarity=mol soluteL soln

5 0
3 years ago
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