Question

What is the value in y in the equation 2(3y+4+2)=196-16?

Answer 1

$(2 \times 3)y = 6y$

$2 \times 4 = 8$

$2 \times 2 = 4$

$6y = - 8 - 4 + 196 - 16$

$6y = 168$

$y = 168 \div 6$

$y = 28$

Answer 2

2(3y+4+2)=196-16 2(3y+6)=180 2(3x28)+6=180 2(84+6)=180 2x 90=180 So y=28