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Assoli18 [71]
3 years ago
15

PLEASE HELPPP ME ITS DUE TODAY

Mathematics
1 answer:
mel-nik [20]3 years ago
3 0

Answer:

Randall: 44, Amy: 35

Step-by-step explanation:

Four years ago, their age added up to 71. Since four years have passed and they've each grown four years older since then, their ages added up together is 79. Here is the equation for Amy: x + (x + 9) = 79. We can simplify to get 35. Now we add 9 to 35 to get Randall's age. So, Amy's age is 35 and Randall's age is 44, and 35 + 44 = 79.

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Jeff is saving to purchase a new basketball that will cost at least $88. He has already saved $32. At least 7) Jeff is saving to
Mariulka [41]
The answer is 224 
becs 32*7=224
4 0
3 years ago
12. The sum of three consecutive integers is 12 more than twice the largest integer. Which of the following
baherus [9]

Answer:

OPTION 4

Step-by-step explanation:

Let the three consecutive numbers be n, (n + 1) and (n + 2).

Note that the largest number of the three is (n + 2) and the smallest is n.

So, according to the given data, the sum of all the three integers is equal to 1 more than twice more than the largest number.

Writing it mathematically, we have:

n + (n + 1) + (n + 2) = 12 + 2(n + 2)

This is OPTION (4) and is the answer,

5 0
3 years ago
Does someone know this? :)
kvv77 [185]

Answer:

Your answer would be

- 2/25 x^3a^3

Or vice versa with the variables

- 2/25 a^3x^3

TO solve it’s pretty simple if you do it correctly.

So with all the variables in the two multiples, you can find a way to combine them

So ignoring everything else you’d get

a^2x * x^2a

You we can see the difference,

theres a^2 and a

Whilst there is also x^2 and x

Now we can combine them

a^3 x^3

Now we can do the normal multipacation with the fraction

2/5 * - 1/5 which is -2/25

Now combine

ANd you got it :D

3 0
2 years ago
A rectangle has a length of x + 2, a width of 7, and a perimeter of 32. The value of x is ?
Anika [276]
X=16
Need an explanation?

7 0
3 years ago
Read 2 more answers
What are the possible numbers of positive, negative, and complex zeros of f(x)= -x^6 + x^5 - x^4 + 4x^3 - 12x^2 + 12?
inn [45]
Using Descartes' Rule of Signs:
The signs are: - + - + - +
There are 5 signs changes in this sequence, so there could be either 5, 3, or 1 positive roots.
If we negate the terms with odd numbers (x^5, x^3), we end up with the signs: - - - - - +
Since there is 1 sign change, there can be only 1 negative root.
This means the positive and negative roots can either be 6, 4, or 2.
Since the total number of roots cannot exceed 6, there are either 0, 2, or 4 complex roots.
6 0
3 years ago
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