Density = 7.36 grams ÷ (2 cm × 2 cm × 2cm) = 0.92 g/cm^3
Assuming ideal conditions, Boyle's law says that
<em>P₁ V₁ </em>= <em>P₂</em> <em>V₂</em>
where <em>P₁ </em>and <em>V₁</em> are the initial pressure and temperature, respectively, and <em>P₂</em> and <em>V₂</em> are the final pressure and temperature.
So you have
(455 mm Hg) (56.5 m³) = (632 mm Hg) <em>V₂</em>
==> <em>V₂</em> = (455 mm Hg) (56.5 m³) / (632 mm Hg) ≈ 40.7 m³
QUESTION:
WHAT IS THE MAGNITUDE OF THE MAGNETIC FIELD AT RIGHT ANGLES TO THE PROTON'S PATH?
ANSWER:
=<em><u>☑</u></em><em><u> </u></em><em><u>2</u></em><em><u>.</u></em><em><u>4</u></em><em><u> </u></em><em><u>T</u></em>
Answer:
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