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Ad libitum [116K]
2 years ago
13

What is chronology?

Physics
2 answers:
gavmur [86]2 years ago
8 0

Answer:

The correct order of events over time

Ket [755]2 years ago
7 0

Answer:Its B

Explanation:Can I please have brainliest

You might be interested in
.Find the uncertainty in a calculated electrical potential difference from the measurements of current and resistance. Electric
maw [93]

Answer:

a) The uncertainty in calculated V, ΔV = 25.3

b) The uncertainty in calculated v, Δv = 0.41 m/s

c) The uncertainty in calculated V, ΔV = 22.2 V

Explanation:

We'll use Upper-Lower Bounds method of uncertainty to estimate the uncertainties.

a) I = 5.1 A, ΔI = 0.3 A

I = (5.1 ± 0.3) A

R = 77.5 ohms, ΔR = 0.4 ohms

R = (77.5 ± 0.4) ohms

V = IR = 5.1 × 77.5 = 395.25 V

The lower bound for the voltage will be calculated using the lower bounds for the current and resistance

Iₗ = 5.1 - 0.3 = 4.8 A

Rₗ = 77.5 - 0.4 = 77.1 ohms

Vₗ = 4.8 × 77.1 = 370.08 V

The upper bound for the voltage will be calculated using the upper bounds for the current and resistance

Iᵤ = 5.1 + 0.3 = 5.4 A

Rᵤ = 77.5 + 0.4 = 77.9 ohms

Vᵤ = 5.4 × 77.9 = 420.66 V

The average of the differences from the mean voltage/true value is 25.3 V

V = 395.25 V, Δ = 25.3V

V = (395.25 ± 25.3) V

b) x = 2.9 m, Δx = 0.3 m

x = (2.9 ± 0.3) m

t = 4.4 s, Δt = 1.8 s

t = (4.4 ± 1.8) ohms

v = x/t = 2.9/4.4 = 0.659 m/s

The lower bound for average speed will be calculated using the lower bounds for distance and upper bounds for time.

xₗ = 2.9 - 0.3 = 2.6 m

tᵤ = 4.4 + 1.8 = 6.2 s

vₗ = 2.6/6.2 = 0.419 m/s

The upper bound for the average speed will be calculated using the upper bound for the distance and lower bound for time

xᵤ = 2.9 + 0.3 = 3.2 m

tₗ = 4.4 - 1.8 = 2.6 s

vᵤ = 3.2/2.6 = 1.231 m/s

The average of the differences from the mean average speed/true value is 0.41 m/s

v = 0.659 m/s, Δv = 0.41 m/s

v = (0.659 ± 0.41) m/s

c) ) I = 9.8 A, ΔI = 0.5 A

I = (9.8 ± 0.5) A

R = 40.5 ohms, ΔR = 0.2 ohms

R = (40.5 ± 0.2) ohms

V = IR = 9.8 × 40.5 = 396.9 V

The lower bound for the voltage will be calculated using the lower bounds for the current and resistance

Iₗ = 9.8 - 0.5 = 9.3 A

Rₗ = 40.5 - 0.2 = 40.3 ohms

Vₗ = 9.3 × 40.3 = 374.79 V

The upper bound for the voltage will be calculated using the upper bounds for the current and resistance

Iᵤ = 9.8 + 0.5 = 10.3 A

Rᵤ = 40.5 + 0.2 = 40.7 ohms

Vᵤ = 10.3 × 40.7 = 419.21 V

The average of the differences from the mean voltage/true value is 22.2 V

V = 396.9 V, Δ = 22.2 V

V = (396.9 ± 22.2) V

7 0
3 years ago
You punt a ball straight up at 20 m/s. What is the balls hangtime
Natalija [7]

The hang time of the ball is 4.08 s

Explanation:

The ball is in free fall motion: this means that it is acted upon gravity only, so its acceleration is the acceleration of gravity,

a=g=-9.8 m/s^2

downward (the negative sign refers to the downward direction).

Since this is a uniformly accelerated motion, we can solve the problem by using the following suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

First we calculate the time it takes for the ball to reach the maximum height, where the velocity is zero:

v = 0

Substituting:

u = +20 m/s

a=-9.8 m/s^2

we find t

t=\frac{v-u}{a}=\frac{0-20}{-9.8}=2.04 s

The motion of the ball is symmetrical, so the total time of flight is just twice the time needed to reach the maximum height, therefore:

T=2t=2(2.04)=4.08 s

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

4 0
3 years ago
28. Identify whether the following objects are in
Marianna [84]

Answer:

a. A baseball after it has been  hit - not in free fall

b. A rock that is thrown in the  air - not in free fall

c. The moon - free-fall

d. A paper airplane - not in free fall

e. A bird flying - not in free fall

Explanation:

  1. The free-fall is defined as the falling of an object due to the action of gravity. The object is not experiencing any other force neglecting the air resistance.
  2. If an object is in free-fall, the direction of its motion is directed towards the center of the earth. It does not have a horizontal component of velocity.
  3. If the body is under free-fall, but a centripetal force acts on it where it is equal to the gravitational force at that point. The object will have two components of velocity along the tangential line, perpendicular to the radius of the orbit.

a. A baseball after it has been  hit - not in free fall according to point 1 & 2.

b. A rock that is thrown in the  air - not in free fall according to point 1.

c. The moon - free-fall according to point 3.

d. A paper airplane - not in free fall according to point 1 & 2.

e. A bird flying - not in free fall according to point 1 & 2.

7 0
3 years ago
Which correctly lists three planets that have rings?
Softa [21]

Answer:

D.

Explanation:

All our gas giants have rings

7 0
3 years ago
Review. One electron collides elastically with a second electron initially at rest. After the collision, the radii of their traj
DochEvi [55]

The energy of the incident electron in keV is 5.51× 10—²² keV.

Capacity or ability to do work is termed energy. Energy exists in various forms. It can be in the form of mechanical, potential, thermal, kinetic, and many other forms. Joules is the SI of the energy. The potential energy of a system is defined as the energy stored due to its position. While kinetic energy is defined as the energy

stored due to its position.

Radius1 of the trajectory = 1.00 cm

Radius2 of the trajectory = 2.4 0 cm

The magnitude of the uniform magnetic field = 0.0440 T

A Uniform magnetic field is perpendicular to the trajectories.

The velocity of the incident electron is,

v =  \frac{eBR}{m}

The energy of the incident electron is,

K =  \frac{1}{2} mv ^{2}

K =  \frac{1}{2} \frac{(eBR)}{m}^{2}

The energy in keV is,

1-kilo electron volt = 1000 electron volts

1 keV = 1000 eV

1 \: eV =  \frac{1}{1000} \:  keV

= \frac{ K}{1000}

=  \frac{eB ^{2} R ^{2} }{2000m}

= 5.51 \times 10 ^{ - 22}  \: keV

Therefore, the energy of the incident electron in keV is 5.51× 10—²² keV.

To know more about electrons, refer to the below link:

brainly.com/question/1255220

#SPJ4

6 0
1 year ago
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