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Semenov [28]
3 years ago
13

A magnet is placed inside a small cube which is placed inside a larger cube which has eight times the volume of the smaller cube

How does the net magnetic flux through the large cube compare to that through the smaller cube?
Physics
1 answer:
alexdok [17]3 years ago
4 0

Answer:

The magnetic flux through the two cubes is zero in both cases

Explanation:

To answer this question, we have to think about the nature of magnetic fields.

In fact, we know that magnetic sources always exist only as magnetic dipoles: this means that a magnet always has a north pole (from which the magnetic field lines go away) and a south pole (into which the magnetic field lines return). There exist no magnetic monopoles: even when we cut a magnet in a half, we end up having two magnets, each of them having its own north pole and south pole.

A direct consequence of this fact is that if we take a closed surface, such as a cube surrounding the magnet, the magnetic flux through the cube is always zero. This is because all the field lines going out the surface of the cube always return inside the cube on another point. Since the magnetic flux basically represents the number of field lines passing through the surface of the cube, this means that the net positive magnetic flux (lines going out of the cube) is equal to the net negative magnetic flux (lines going into the cube).

As a result, the magnetic flux is zero for both the smaller cube and the larger cube.

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Air flows through an adiabatic turbine that is in steady operation. The air enters at 150 psia, 900oF, and 350 ft/s and leaves a
Nonamiya [84]

Answer:

1486.5\frac{Btu}{s}

Explanation:

The inlet specific volume of air is given by:

v_1=\frac{RT_1}{P_1}\\\\v_1=\frac{(0.3704\frac{psia.ft^3}{lbm.R})(1360R)}{150psia}\\\\v_1=3.358\frac{ft^3}{lbm} \ \ \ \  \ \  \ \ \...i

The mass flow rates is expressed as:

\dot m=\frac{1}{v_1}A_1V_1\\\\\dot m=\frac{1}{3.358ft^3/psia}(0.1ft^2)(350ft/s)\\\\\dot m=10.42\frac{lbm}{s}

The energy balance for the system can the be expresses in the rate form as:

E_{in}-E_{out}=\bigtriangleup \dot E=0\\\\E_{in}=E_{out}\\\\\dot m(h_1+0.5V_1^2)=\dot W_{out}+\dot m(h_2+0.5V_2^2)+Q_{out}\\\\\dot W_{out}=\dot m(h_2-h_1+0.5(V_2^2-V_1^2))=-m({cp(T_2-t_1)+0.5(V_2^2-V_1^2)})\\\\\\\dot W_{out}=-(10.42lbm/s)[(0.25\frac{Btu}{lbm.\textdegree F})(300-900)\textdegree F+0.5((700ft/s)^2-(350ft/s)^2)(\frac{1\frac{Btu}{lbm}}{25037ft^2/s^2})]\\\\\\\\=1486.5\frac{Btu}{s}

Hence, the mass flow rate of the air is 1486.5Btu/s

5 0
2 years ago
A boy throws a ball with an initial velocity of 19.6 m/s. What maximum height does the ball reach?
Wewaii [24]
<h2>Hello!</h2>

The answer is: 19.59 m

<h2>Why?</h2>

Since there is no information about the launch type, we can assume that the ball is thrown vertically upward.

When the ball reaches the maximum height, just at that moment, the velocity turns to 0, and after that moment, the ball starts falling, so:

We will use the following formula:

Vf^2=Vi^2+2*g*s

Where:

Vf= Final velocity = 0

Vi= Initial velocity = \frac{19.6m}{s}

g = Gravity Acceleration = \frac{9.81m}{s^{2} }

s = Traveled distance

0=19.6^2+2*-9.81*s\\s=\frac{19.6^2}{2*9.81}=\frac{384.16}{19.62}=19.59m

Have a nice day!

8 0
3 years ago
A boat, whose speed in still water is 8.0 m/s, crosses a river with a current of 6.0 m/s. If the boat heads perpendicular to the
kirill [66]

Answer: D

Rs = 10.0 m/s

The speed of the boat relative to an observer standing on the shore as it crosses the river is 10.0m/s

Explanation:

Since the boat is moving perpendicular to the current of the river, the speed of the boat has two components.

i. 8.0m/s in the direction perpendicular to the current

ii. 6.0m/s in the direction of the current.

So, the resultant speed can be derived by using the equation;

Rs = √(Rx^2 + Ry^2)

Taking

Ry = 8.0m/s

Rx = 6.0m/s

Substituting into the equation, we have;

Rs = √(6.0^2 + 8.0^2)

Rs = √(36+64) = √100

Rs = 10.0 m/s

The speed of the boat relative to an observer standing on the shore as it crosses the river is 10.0m/s

3 0
3 years ago
Read 2 more answers
Four objects are situated along the y axis as follows: a 1.93-kg object is at +2.91 m, a 2.95-kg object is at +2.43 m, a 2.41-kg
Anna [14]

Answer:

0.958 m

Explanation:

So the total mass of the system is

M = 1.93 + 2.95 + 2.41 + 3.99 = 11.28  kg

let y be the distance from the center of mass to the origin. With the reference to the origin then we have the following equation

My = m_1y_1 + m_2y_2 +m_3y_3 + m_4y_4

11.28y = 1.93*2.91 + 2.95*2.43 + 2.41*0 + 3.99*(-0.496) = 10.806

y = \frac{10.806}{11.28} = 0.958 m

So the center of mass is 0.958 m from the origin

3 0
2 years ago
What is the surface tension of water? of rubbing alcohol? was your prediction correct or incorrect?
kompoz [17]

Rubbing water (isopropyl alcohol) has lesser surface tension than that water.

Water possesses a surface tension of 72 dynes/cm.

Whereas rubbing alcohol has a surface tension of 23 dynes/cm.

<h3>what is surface tension?</h3>

Surface tension is the propensity of liquid surfaces at rest to shrink to the smallest possible surface area.

Because the atoms on the outside of the molecules (often hydrogens) lack strong hydrogen bonding capabilities, most organic liquids have very low surface tensions. Because isopropanol contains just 28%, OH and the remainder is CH or CH3, the linkages that hold a droplet together are few and far between.

The only substance with a higher surface tension than water is liquid mercury (450 dyne/cm).

Learn more about surface tension here:

brainly.com/question/19390213

#SPJ4

6 0
2 years ago
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