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mr Goodwill [35]

3 years ago

10

Pls will give brainliest!! How is an atom categorized when it gains an extra electron, and how is it categorized when it loses a

n electron?

1 answer:

padilas [110]3 years ago

6 0

If it gains an extra electron, it becomes negatively charged and categorised as anion.
If it loses an electron, it becomes positively charged and categorised as cation.

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The Hawaiian islands formed when molten material erupted from the ocean floor. As the lava flowed out, cooled, and hardened, mas

lara [203]

Answer:

Explanation:

The most common type of igneous rock making up the Hawaiian island chain is Mafic rock. Furthermore, the most common type of Mafic rock is basalt.

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3 years ago

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3 years ago

A potter's wheel is rotating around a vertical axis through its center at a frequency of 2.0 rev/srev/s . The wheel can be consi

vagabundo [1.1K]

Answer:1.7 rev/s

Explanation:

Given

Frequency of wheel $N_1=2\ rev/s$

angular speed $\omega_1=2\pi N_1=4\pi\ rad/s$

mass of wheel $m_1=4.5\ kg$

diameter of wheel $d_1=0.30\ m=30\ cm$

radius of wheel $r_1=\frac{d_1}{2}=\frac{30}{2}=15\ cm$

mass of clay $m_2=2.8\ kg$

the radius of the chunk of clay $r_2=8\ cm$

Moment of inertia of Wheel

$I_1=\dfrac{m_1r_1^2}{2}=\dfrac{4.5\times 15^2}{2}\ kg-cm^2$

Combined moment of inertia of wheel and clay chunk

$I_2=\dfrac{m_1r_1^2}{2}+\dfrac{m_2r_2^2}{2}=\dfrac{4.5\times 15^2}{2}+\dfrac{2.8\times 8^2}{2}\ kg-cm^2$

Conserving angular momentum

$\Rightarrow I_1\omega_1=I_2\omega_2\\\Rightarrow \dfrac{4.5\times 15^2}{2}\cdot 4\pi=(\dfrac{4.5\times 15^2}{2}+\dfrac{2.8\times 8^2}{2})\omega_2\\\\\Rightarrow \omega _2=\dfrac{4\pi }{1+\dfrac{2.8}{4.5}\times (\dfrac{8}{15})^2}=\dfrac{4\pi}{1+0.1769}=0.849\times 4\pi$

Common frequency of wheel and chunk of clay is

$\Rightarrow N_2=\dfrac{4\pi \times 0.849}{2\pi}=1.698\approx 1.7\ rev/s$

5 0

3 years ago

Light that has a wavelength of 600 nm strikes a metal surface, and a stream of electrons is ejected from the surface. If light o

Anni [7]

Answer:

The maximum kinetic energy of the electrons emitted from the surface will be greater.

Option 3 is correct.

Explanation:

Given that,

Wavelength $\lambda_{1}=600\ nm$

Wavelength $\lambda_{2}=500\ nm$

We need to calculate the energy for first wavelength

Using formula of energy

$E=hf$

$E=h\dfrac{c}{\lambda}$

Put the value into the formula

$E_{1}=6.67\times10^{-34}\times\dfrac{3\times10^{8}}{600\times10^{-9}}$

$E_{1}=3.33\times10^{-19}\ J$

We need to calculate the energy for second wavelength

Put the value into the formula

$E_{2}=6.67\times10^{-34}\times\dfrac{3\times10^{8}}{500\times10^{-9}}$

$E_{2}=4.002\times10^{-19}\ J$

So, E₂>E₁

Hence, The maximum kinetic energy of the electrons emitted from the surface will be greater.

8 0

3 years ago

Imagine that the ball on the left is given a nonzero initial velocity in the horizontal direction, while the ball on the right c

masya89 [10]

Answer:

vₓ = xg/2y

Explanation:

In this question, let us find the time it takes for the ball on the right that has zero initial velocity to reach the ground.

By newton equation of motion we know that

y = v₀ t - ½ g t²

t = 2y / g

This is the time it takes for the ball on the right to reach the ground; at this time the ball on the left travels a distance

vₓ = x/t

vₓ = xg/2y

vₓ = xg/2y

Where we assume that x and y are known.

7 0

3 years ago