Answer:
26.51 N
Explanation:
Using
F = mω²r + mg ....................... Equation 1
Where F = maximum tension in the string, ω = angular velocity, r = radius of the circle formed/ Length of the ball, g = acceleration due to gravity
Also,
ω = 2π/T........................ Equation 2
Where T = Period, π = Pie
Substitute equation 2 into equation 1
F = [mr(2π/T)²]+mg
F = [mr4π²/T²]+mg.................... Equation 3
Given: m = 1.35 kg, r = 1.10 m, T = 2.10 s, g = 9.8 m/s², π = 3.14
Substitute into equation 3
F = 1.35(1.1)(4)(3.14²)/2.1² + 1.35(9.8)
F = 13.28+13.23
F = 26.51 N.
Hence the maximum tension in the string = 26.51 N