The area of the entire sector is ![(\pi)(6^{2}) \left(\frac{60}{360} \right)=6\pi](https://tex.z-dn.net/?f=%28%5Cpi%29%286%5E%7B2%7D%29%20%5Cleft%28%5Cfrac%7B60%7D%7B360%7D%20%5Cright%29%3D6%5Cpi)
The area of the triangle OAB is
.
So, the area of the segment is ![\boxed{6\pi-9\sqrt{3}}](https://tex.z-dn.net/?f=%5Cboxed%7B6%5Cpi-9%5Csqrt%7B3%7D%7D)
L*W*H for area. You need to multiply the length then width then height. The answer would equal 270
Total surface area equals area of 5 rectangular faces + 2 pentagonal faces
Area of 5 rectangular faces
![=5 \times 6 \times 9 km^2](https://tex.z-dn.net/?f=%3D5%20%5Ctimes%206%20%5Ctimes%209%20km%5E2)
![=270 km^2](https://tex.z-dn.net/?f=%3D270%20km%5E2)
Area of 2 pentagonal faces can be found by drawing 5 isosceles triangles with height as shown in the diagram and multiply the result by 2.
![=5 \times \frac{1}{2} \times 9 \times 6.2 \times 2km^2](https://tex.z-dn.net/?f=%3D5%20%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%209%20%5Ctimes%206.2%20%5Ctimes%202km%5E2)
![=279km^2](https://tex.z-dn.net/?f=%3D279km%5E2)
The toatal surface area is
![=270+279=549 km^2](https://tex.z-dn.net/?f=%3D270%2B279%3D549%20km%5E2)
The correct answer is A
Answer:
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Answer: $475
Step-by-Step Explanation:
Let cost of a Garden Table be ‘x’
Let cost of a Bench be ‘y’
Framing the Equations :-
=> x + y = 912 (Eq. 1)
x = y - 38
=> x - y = -38 (Eq. 2)
On Adding Eq. 1 and Eq. 2, we get :-
2x = 874
x = 874/2
=> x = 437
Therefore, x = 437
Substitute value of ‘x’ in Eq. 1 :-
x + y = 912
437 + y = 912
y = 912 - 437
=> y = 475
Therefore, y = 475
Hence,
Cost of Garden Table = $437
Cost of Bench = $475