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2 years ago

Determine the GCF of 18xy and 12xy

Mathematics

1 answer:

Roman55 [17]2 years ago

6 0

Answer:

If im correct im pretty sure its 6xy

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Which of the following could be the lengths of the sides of a 45°-45°-90° triangle?

Sunny_sXe [5.5K]

Answer would be 6.
i've done this one before.

7 0

2 years ago

If y varies directly as x, and x = 48 when y = 6, find y when x = 12.

pentagon [3]

Answer: Each time the pentagon is rotated , it maps back onto itself. There are five values of for which the pentagon maps back onto itself. This is the same as the number of sides of the pentagon.

6 0

3 years ago

Read 2 more answers

Helen spent $145 for shoes. This was $55 more than twice what she spent for a bag. How much was the bag?

marin [14]

Answer:

45 DOLLARS

Step-by-step explanation:

For these kind of problems, write an equation to figure out the answer.

55 + 2x = 145

x represents the bag cost

145 is the shoe cost

Take out the constant, which is 55, from both sides. A constant is a useful term you should learn.

The result is: 2x = 90

Divide 2x by 2, to get x, which is the bag cost, by itself.

Result: x= 45

Since x is the bag cost, the bag costs 45 dollars

Please mark me brainliest

8 0

3 years ago

How many pairs can be made from 8 different objects?

NeTakaya

The correct answer is 31. I did it incorrectly the first time, but the answer is 31. :-) Thanks Olivia!

3 0

3 years ago

Find y as a function of x if y"' + 9y' = 0, y(0) = 6, y'(0) = 9, y"(0) = 18. y(x) =

Andreas93 [3]

Answer:

y(x) = 8 - 2cos 3x + 3sin 3x

Step-by-step explanation:

Given the equation:

y''' + 9y' = 0

The characteristic equation :

⇒r³ + 9r =0

Solving for r, we get r = 0 and r = ± 3i

The general equation for such equation is :

y = C₁ + C₂cos 3x + C₃sin 3x

Given:

y(0) = 6

Thus, Applying in the above equation, we get

6 = C₁ + C₂ .......................................................1

Differentiating y , we get:

y' = -3C₂sin 3x + 3C₃cos 3x

Given:

y'(0) = 9

Thus, Applying in the above equation, we get

9 = 3C₃

or,

C₃ = 3

Differentiating y' , we get:

y'' = -9C₂cos 3x - 9C₃sin 3x

Given:

y''(0) = 18

Thus, Applying in the above equation, we get

18 = -9C₂

or,

C₂ = -2

Applying in equation 1 , we get:

C₁ = 8

Thus,

y(x) = 8 - 2cos 3x + 3sin 3x

4 0

3 years ago