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Andrei [34K]
3 years ago
7

2 + (x + 4) Help me out

Mathematics
2 answers:
MariettaO [177]3 years ago
7 0

Answer:

x + 6

Step-by-step explanation:

If you dont know the value of x you cant solve the problem fully

Daniel [21]3 years ago
6 0

Answer:

6+x

Step-by-step explanation:

2+(x+4)

=2+x+4

=6+x

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PLEASE HELP
MaRussiya [10]

Answer:

x=54

Step-by-step explanation:

3x-52=2x+2

3x-2x =52 +2

6 0
3 years ago
WILL MARK BRAINLIEST Beth has a graph to represent her distance when she runs 5 miles per hour. What would the point (2, 10) mea
mestny [16]

Answer:

Ok so you have to find how much it goes up at a time. So the first one is 1,5. Then multiply both by 5 to get 5,25. That is your answer then. The graph will have 5 on the bottom and 25 on the side.

Step-by-step explanation:

8 0
4 years ago
With decimal is equivalent to 76/9
Anni [7]

Answer:

8.4

Step-by-step explanation:

76 ÷ 9 = 8.44444444

= 8.4 (rounded)

hope this helps!

6 0
2 years ago
Read 2 more answers
An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

n_1=155

$p_2=\frac{86}{155}=0.554839

n_2=155

The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

                                     $=2 \times 0.085667$

                                     = 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

8 0
3 years ago
The early version of a cell phone was 93 millimeters
Basile [38]
It is 78.12
Explanation 16 percent of 93 is 78.12
3 0
4 years ago
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