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2 years ago

A cyclist travels at an average speed of 18 mph for 2 hours. How far did she travel in miles?

Mathematics

1 answer:

olya-2409 [2.1K]2 years ago

5 0

Answer:

Step-by-step explanation:

18 miles per hour so for 2 hours which is double, she should have traveled 36 miles.

Good Luck!

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Solve: z5 + 3 = −35

Fudgin [204]

Answer:

z= - 5 √ 38

Step-by-step explanation:

take the root of both sides

you can factor each set and make them equal to zero

8 0

3 years ago

Consider the given right triangle. If angle B = 43 degrees and c = 26.7 meters, find a.

Nady [450]

Answer: Side a equals 19.5 metres

Step-by-step explanation: Consider the right angled triangle as shown in the picture attached. The triangle has been drawn with angle measuring 43 degrees, side c (line AB) measuring 26.7 m and side a (line CB) is yet unknown.

A right angled triangle can be solved if at least one side and an angle are available. In this question we shall apply the trigonometric ratios since we have one angle which shall be the reference angle (43°). Also we have an hypotenuse (the side facing the right angle) and an unknown side which is the adjacent (which lies between the right angle and the reference angle).

Cos B = Adjacent/Hypotenuse

Cos 43 = a/26.7

Cos 43 x 26.7 = a

0.7314 x 26.7 = a

19.52714 = a

a ≈ 19.5 (rounded to the nearest tenth)

Therefore the length of side a equals 19.5 metres.

3 0

3 years ago

Read 2 more answers

John runs to the market and comes back in 15 minutes. His speed on the way to the market is 5m/s and his speed on the way back i

katen-ka-za [31]

Answer:

The distance to the market is 2000 m

Step-by-step explanation:

∵ John runs to the market and comes back in 15 minutes

→ Change the min. to the sec. because the unit of his speed is m/s

∵ 1 minute = 60 seconds

∴ 15 minutes = 15 × 60 = 900 seconds

→ Assume that t1 is his time to the market and t2 is his time from

the market

∵ t1 + t2 = 15 minutes

∴ t1 + t2 = 900 ⇒ (1)

→ Assume that the distance to the market is d

∵ His speed on the way to the market is 5m/s

∵ Time = Distance ÷ Speed

∴ t1 = d ÷ 5 ⇒ (1 ÷ 5 = 0.2)

∴ t1 = 0.2d ⇒ (2)

∵ His speed on the way back is 4m/s

∴ t2 = d ÷ 4 ⇒ (1 ÷ 4 = 0.25)

∴ t2 = 0.25d ⇒ (3)

→ Substitute (2) and (3) in (1)

∵ 0.2d + 0.25d = 900

∴ 0.45d = 900

→ Divide both sides by 0.45

∴ d = 2000 m

∴ The distance to the market = 2000 m

8 0

3 years ago

Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178

Katarina [22]

Answer:

$2x+178\geq 2000$

Step-by-step explanation:

Let, the number of cans collected by Shane = x.

So, the number of cans collected by Abha = x + 178.

Since, at least 2000 cans are required to be collected.

Thus, we have the inequality,

Number of cans by Shane + Number of cans by Abha ≥ 2000.

i.e. $x+(x+178)\geq 2000$

i.e. $2x+178\geq 2000$

Thus, the required inequality is $2x+178\geq 2000$ .

4 0

3 years ago

H(n) - 4n - 4; Find h(0)

9966 [12]

4h hi fing h0 9 p h)n 0

6 0

3 years ago