Answer:
0.6210
Step-by-step explanation:
Given that a Food Marketing Institute found that 39% of households spend more than $125 a week on groceries
Sample size n =87
Sample proportion will follow a normal distribution with p =0.39
and standard error = 
the probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41
=
There is 0.6210 probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41
Answer:
everywhere except between 2 and 5
(between -inf and 2 and between 5 and inf)
Step-by-step explanation:
pls brainlist
<span>2x + 5 =8x
6x = 5
x = 5/6
12x = 12(5/6) = 10</span>
Answer:
4
Step-by-step explanation:
First n(AUB)=n(E) - n((AUB)')
So n(AUB) = 40 - 6 = 34
Now all u hv to do is use the formulae,
n(AUB) = n(A) + n(B) - n(ANB)
So when u substitute above values,
34=22 + n(B) - 8
So,
n(B) = 4
X = small van capacity, y = larger van capacity
y = x + 6
2x + y = 57
now we sub in x + 6 for y
2x + x + 6 = 57
3x + 6 = 57
3x = 57 - 6
3x = 51
x = 51/3
x = 17
y = x + 6
y = 17 + 6
y = 23
small van (x) has 17 seats and large van (y) has 23 seats
