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3 years ago

Help me with this tooo! It is the question that is not filled in

Mathematics

1 answer:

Kazeer [188]3 years ago

3 0

you will have 8 tables so

72 chair / 8 tables = 9 chair per table

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Integrate G(x,y,z)equalsz over the parabolic cylinder yequalszsquared, 0less than or equalsxless than or equals2, 0less than

yKpoI14uk [10]

I gather you're supposed to compute the integral of $G(x,y,z)=z$ over a surface $S$ that is the part of the parabolic cylinder $y=z^2$ with $0\le x\le2$ and $0\le z\le\frac{\sqrt{15}}2$ .

We can parameterize $S$ by

$\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k$

with the given constraints on $x$ and $z$ . Take the normal vector to $S$ to be

$\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k$

so that the surface element is

$\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz$

Then in the integral, we have

$\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}$

5 0

3 years ago

Convert the polar representation of this complex number into its standard form z=4(cos150+isin150).

Katen [24]

Answer:

Step-by-step explanation:

Using the exact values

cos150° = - cos30° = - $\frac{\sqrt{3} }{2}$

sin150° = sin30° = $\frac{1}{2}$

Given

z = 4(cos150° + isin150° ) , substitute values

= 4(- $\frac{\sqrt{3} }{2}$ + $\frac{1}{2}$ i )

= - 2 $\sqrt{3}$ + 2i , that is

(- 2 $\sqrt{3}$ , 2 ) → B

7 0

3 years ago

If y varies directly as x and y=15 when x =5, what is the value of y when x = 15?

yulyashka [42]

Y=5 just flip the question sort of

7 0

3 years ago

1/2x+5=10 what is the number of the variable

ki77a [65]

I think what your asking for is that x=10

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3 years ago

Read 2 more answers

PLEASE HELP ASAP!!! WILL MARK BRAINLIEST!!! CORRECT ANSWER ONLY PLEASE!!! Hugh described two substances which participate in pho

Brrunno [24]

All if it are wrong
3

7 0

3 years ago