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scZoUnD [109]
3 years ago
11

Need help to solve question

Mathematics
1 answer:
jeka57 [31]3 years ago
4 0

Answer:

I think its A...

Step-by-step explanation:

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URGENT
Dmitry [639]

Answer:

AAA

Step-by-step explanation:

angles are equal because two pairs are of alternate angles and one of vertically opposite angles

8 0
3 years ago
the difference between 2 whole number is 66 the ratio of the 2 whole number is 2.5 what are the two numbers​​
ch4aika [34]

Given :difference between 2 whole number = 66ratio of the 2 whole number =2:5Let:1 whole number be 2x2 whole number be 5xA/Q

difference between 2 whole number = 66

Let's turn it into algebraic equation:

5x - 2x = 663x= 66x =66 /3x =22

Now Let's put value of x to find two whole numbers

Finaly :1 whole number = 2x1 whole number = 2×221 whole number =44

2 whole number = 5x2 whole number = 5×222 whole number = 110

3 0
3 years ago
Arrange these functions from the greatest to the least value based on the average rate of change in the specific interval
oee [108]
The average r. of c. of a function f(x) on an interval [a,b] is:

  f(b) - f(a)
--------------
    b-a

You'll need to apply this to all four of the given functions.

First function:  f(x) = x^2 + 3x
a= -2; b= 3

Then the ave. r. of c. for this function on this interval is:

    18  - (-2)            20
------------------ = ---------- = 4.  y increases by 4 for every unit increase in x.
      3-(-2)                5

Do the same thing for the other 3 functions.

Then arrange your four results in descending order (greatest to least).

5 0
3 years ago
Find the values of the sine, cosine, and tangent for ZA C A 36ft B <br> 24ft
Reptile [31]
<h2>Question:</h2>

Find the values of the sine, cosine, and tangent for ∠A

a. sin A = \frac{\sqrt{13} }{2},  cos A = \frac{\sqrt{13} }{3},  tan A = \frac{2 }{3}

b. sin A = 3\frac{\sqrt{13} }{13},  cos A = 2\frac{\sqrt{13} }{13},  tan A = \frac{3}{2}

c. sin A = \frac{\sqrt{13} }{3},  cos A = \frac{\sqrt{13} }{2},  tan A = \frac{3}{2}

d. sin A = 2\frac{\sqrt{13} }{13},  cos A = 3\frac{\sqrt{13} }{13},  tan A = \frac{2 }{3}

<h2>Answer:</h2>

d. sin A = 2\frac{\sqrt{13} }{13},  cos A = 3\frac{\sqrt{13} }{13},  tan A = \frac{2 }{3}

<h2>Step-by-step explanation:</h2>

The triangle for the question has been attached to this response.

As shown in the triangle;

AC = 36ft

BC = 24ft

ACB = 90°

To calculate the values of the sine, cosine, and tangent of ∠A;

<em>i. First calculate the value of the missing side AB.</em>

<em>Using Pythagoras' theorem;</em>

⇒ (AB)² = (AC)² + (BC)²

<em>Substitute the values of AC and BC</em>

⇒ (AB)² = (36)² + (24)²

<em>Solve for AB</em>

⇒ (AB)² = 1296 + 576

⇒ (AB)² = 1872

⇒ AB = \sqrt{1872}

⇒ AB = 12\sqrt{13} ft

From the values of the sides, it can be noted that the side AB is the hypotenuse of the triangle since that is the longest side with a value of 12\sqrt{13} ft (43.27ft).

<em>ii. Calculate the sine of ∠A (i.e sin A)</em>

The sine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the hypotenuse side of the triangle. i.e

sin Ф = \frac{opposite}{hypotenuse}             -------------(i)

<em>In this case,</em>

Ф = A

opposite = 24ft (This is the opposite side to angle A)

hypotenuse = 12\sqrt{13} ft (This is the longest side of the triangle)

<em>Substitute these values into equation (i) as follows;</em>

sin A = \frac{24}{12\sqrt{13} }

sin A = \frac{2}{\sqrt{13}}

<em>Rationalize the result by multiplying both the numerator and denominator by </em>\sqrt{13}<em />

sin A = \frac{2}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }

sin A = \frac{2\sqrt{13} }{13}

<em>iii. Calculate the cosine of ∠A (i.e cos A)</em>

The cosine of an angle (Ф) in a triangle is given by the ratio of the adjacent side to that angle to the hypotenuse side of the triangle. i.e

cos Ф = \frac{adjacent}{hypotenuse}             -------------(ii)

<em>In this case,</em>

Ф = A

adjacent = 36ft (This is the adjecent side to angle A)

hypotenuse = 12\sqrt{13} ft (This is the longest side of the triangle)

<em>Substitute these values into equation (ii) as follows;</em>

cos A = \frac{36}{12\sqrt{13} }

cos A = \frac{3}{\sqrt{13}}

<em>Rationalize the result by multiplying both the numerator and denominator by </em>\sqrt{13}<em />

cos A = \frac{3}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }

cos A = \frac{3\sqrt{13} }{13}

<em>iii. Calculate the tangent of ∠A (i.e tan A)</em>

The cosine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the adjacent side of the triangle. i.e

tan Ф = \frac{opposite}{adjacent}             -------------(iii)

<em>In this case,</em>

Ф = A

opposite = 24 ft (This is the opposite side to angle A)

adjacent = 36 ft (This is the adjacent side to angle A)

<em>Substitute these values into equation (iii) as follows;</em>

tan A = \frac{24}{36}

tan A = \frac{2}{3}

6 0
3 years ago
3x -2y = -6 and y = x+5
sweet [91]

Answer:

x = 4, y = 9.

Step-by-step explanation:

3x -2y = -6 and y = x+5

Substitute y = x + 5 in the first equation:

3x - 2(x + 5) = -6

3x - 2x - 10 = -6

x = -6 + 10

x = 4

So y = 4 + 5 = 9.

5 0
3 years ago
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