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Irina18 [472]
3 years ago
13

An airline charges an extra fee if a suitcase weighs more than 50 pounds. After packing, Li's suitcase weighs 47.75 pounds. Whic

h inequality can be used to determine how much more weight can be added to the suitcase without going over the 50-pound weight limit? 47.75 + x < 50 47.75 + x Less-than-or-equal-to 50 47.75 + x Greater-than-or-equal-to 50 47.75 + x > 50
Mathematics
2 answers:
Artemon [7]3 years ago
6 0

Answer:

B

Step-by-step explanation:

taking assignment rn on edge 2021

Vinvika [58]3 years ago
4 0

Answer:

47.75 + x Less-than-or-equal-to 50

= 47.75 + x ≤ 50

Step-by-step explanation:

Solving the above Question:

Not going over the 50 pound case mean, less than or equal to 50 pounds

Let the extra pound of weight be represented as x

Hence, the inequality equation that can be used to determine how much more weight can be added to the suitcase without going over the 50-pound weight limit =

47.75 + x ≤ 50

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Congress regulates corporate fuel economy and sets an annual gas mileage for cars. A company with a large fleet of cars hopes to
attashe74 [19]

Answer:

a) Null hypothesis:\mu \leq 30.2  

Alternative hypothesis:\mu > 30.2  

b) X \sim N(\mu=32.12, \sigma=4.83)

And the distribution for the random sample is given by:

\bar X \sim N(\mu=32.12, \frac{\sigma}{\sqrt{n}}=\frac{4.83}{\sqrt{50}}=0.683)

c) t=\frac{32.12-30.2}{\frac{4.83}{\sqrt{50}}}=2.81    

p_v =P(t_{(49)}>2.81)=0.0035  

d) If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is significantly higher than 30.2.  

e) The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct. And for this case is a value to accept or reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation  

\bar X=32.12 represent the sample mean  

s=4.83 represent the sample standard deviation

n=50 sample size  

\mu_o =30.2 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

a. Define the parameter and state the hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 30.2 mpg, the system of hypothesis would be:  

Null hypothesis:\mu \leq 30.2  

Alternative hypothesis:\mu > 30.2  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

b. Define the sampling distribution (mean and standard deviation).

Let X the random variable who represent the variable of interest. And we know that the distribution for X is:

X \sim N(\mu=32.12, \sigma=4.83)

And the distribution for the random sample is given by:

\bar X \sim N(\mu=32.12, \frac{\sigma}{\sqrt{n}}=\frac{4.83}{\sqrt{50}}=0.683)

c. Perform the test and calculate P-value

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{32.12-30.2}{\frac{4.83}{\sqrt{50}}}=2.81    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=50-1=49  

Since is a one right tailed test the p value would be:  

p_v =P(t_{(49)}>2.81)=0.0035  

d. State your conclusion.

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is significantly higher than 30.2.  

e. Explain what the p-value means in this context.

The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct. And for this case is a value to accept or reject the null hypothesis.

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jolli1 [7]

Answer:

GIVEN BY POINTS :-

( -1, 9) , ( 4 , -3)

Here ,

\bullet  \: \:  x _{1} = - 1 \\ \bullet \: \:  x _{2} = 4 \\ \bullet \: \:   y _{1} = 9 \\ \bullet \: \:    y _{2} =  - 3 \\

Using Distance formula :

=  >  \sf d = \sqrt{( {x _{2} - x _{1}) }^{2} + {( {y _{2} - y _{1}) }^{2} } } \\ \\  =  > \sf  d = \sqrt{ ({ 4  + 1)}^{2} + { ( - 3 - 9)}^{2} } \\  \\ =  >  \sf d = \sqrt{ {5}^{2} + {( - 12)}^{2} }  \\ \\  =  > \sf d = \sqrt{25 + 144}  \\ \\  =  > \sf d = \sqrt{169}  \\ \\ =  > \boxed{ \sf{  d = 13\:units }}\\

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larisa [96]

ZOSP= PSQ and

ZPSQ E ZOSR

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Rounded 3,428,583 rounded to the nearest 10,000
densk [106]
Since you want to round to the 10,000 place, you'll want to look at the 2 and the 8 that are next to each other. The 8 makes the two a 3 because it is greater than 5, which gives you 3,430,000. Hope this helped!
8 0
3 years ago
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Identify the equation for the graph shown.
mario62 [17]

Answer:

D

Step-by-step explanation:

The graph shows a y-intercept of 5, and so D is the only answer that could be correct.

8 0
3 years ago
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